Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: What is the value of |y − 1| ? [#permalink]
16 Apr 2013, 08:04

What is the value of |y − 1| ?

(1) (y − 7)(y + 5) = 0 (2) 2y + 10 = 0

For DS question, I think that we don't need to find value of y in (1) and (2).

(1). We have one equation with one variable y (exponent of 2), therefore we can find ly-1l => sufficient (2). We have one equation and one variable y (exponent of 1). Similarly => sufficient.

D

This method is clearly relevant for complex questions.

Re: What is the value of |y − 1| ? [#permalink]
16 Apr 2013, 08:16

Expert's post

tritringuyen wrote:

What is the value of |y − 1| ?

(1) (y − 7)(y + 5) = 0

We have one equation with one variable y (exponent of 2), therefore we can find ly-1l => sufficient

This question is designed in such a way that both the values of y are giving you the same value for |y-1|. Is not necessary that it will be the case all the time. _________________

Re: What is the value of |y − 1| ? [#permalink]
16 Apr 2013, 08:35

vinaymimani wrote:

tritringuyen wrote:

What is the value of |y − 1| ?

(1) (y − 7)(y + 5) = 0

We have one equation with one variable y (exponent of 2), therefore we can find ly-1l => sufficient

This question is designed in such a way that both the values of y are giving you the same value for |y-1|. Is not necessary that it will be the case all the time.

You are right. There are similar questions where the absolute values for the two expressions are not the same.

Here this question is easy. But the questions set by GMAC often tests simple and basic concepts in a complicated way.

Re: What is the value of |y − 1| ? [#permalink]
10 May 2013, 19:07

Bluelagoon wrote:

doe007 wrote:

What is the value of |y − 1| ?

(1) (y − 7)(y + 5) = 0 (2) 2y + 10 = 0

Tricky question. Watch out both the values -5 and 7 gives the same value of |y-1|.So A also qualifies. Hence D

Your are right. With this type of setup, quadratic equations end up with same absolute value in some questions and different absolute values in some questions. Here the question is in a very simple form and can be solved very quickly (15-20 sec). Real GMAT questions may have more complicated form of the equation which will need more time to solve.

On September 6, 2015, I started my MBA journey at London Business School. I took some pictures on my way from the airport to school, and uploaded them on...

When I was growing up, I read a story about a piccolo player. A master orchestra conductor came to town and he decided to practice with the largest orchestra...

I’ll start off with a quote from another blog post I’ve written : “not all great communicators are great leaders, but all great leaders are great communicators.” Being...