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What is the volume of a certain rectangular solid? (1) Two

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What is the volume of a certain rectangular solid? (1) Two [#permalink] New post 09 May 2005, 19:03
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What is the volume of a certain rectangular solid?

(1) Two adjacent faces of the solid have areas 15 and 24, respectively.
(2) Each of two opposite faces of the solid has area 40.


What am I missing here ?
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 [#permalink] New post 09 May 2005, 19:58
It is but isn't "B" suff.....we know areas of all the faces and can calculate the volume. Wording of B seems to be lil off. What u make out of "B" ?
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 [#permalink] New post 09 May 2005, 20:46
banerjeea_98 wrote:
It is but isn't "B" suff.....we know areas of all the faces and can calculate the volume. Wording of B seems to be lil off. What u make out of "B" ?


from B, how do you know the area of all the faces? you might be confused with "Each of two opposite faces of the solid has area 40". i do not think that it means all opposite faces. suppose we have the following faces:
front=a
back=b
right = c
left=d
up=e
down/bottom=f

i think "Each of two opposite faces of the solid has area 40" = either a and b or c and d or e and f have the same area.
hope helps.
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 [#permalink] New post 10 May 2005, 01:41
banerjeea_98 wrote:
It is but isn't "B" suff.....we know areas of all the faces and can calculate the volume. Wording of B seems to be lil off. What u make out of "B" ?



I think MA is right Baner.

Guess you're thinking that "all" the surfaces ("each" opposite pair of surfaces) have an area 40 - which makes the rectangular solid collapse to a cuboid.

I just tried solving the prob:
if length = l, breadth = b and height = h,

(A) lxb = 15, lxh= 24.
Two equations, three variables. Unsolvable.

(B) Two opposite surfaces have area 40 each.
Thus, either, lxb = 40, or hxb = 40 or lxh = 40.
One equation, three variables. Unsolvable.

Combining A and B,
Therefore, 3 equations, three variables. Solvable.
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 [#permalink] New post 10 May 2005, 02:51
At the begining I wanted to say A

We know that the two adjacent faces of the solid have areas 15 and 24, respectively. The faces are ajacent which means that they have a side in common, the best way is to find thefactors of both areas :
15 = 3*5 and 24=3*8 so logically one side is 3, another is 5 and the last one is 8.

However I realized later that I didn't take into account the possibility to get some decimal numbers.... :oops: :?
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 [#permalink] New post 10 May 2005, 06:43
yeah...OA is "C"....state 2 threw me off. I still think "B" is poorly worded.
  [#permalink] 10 May 2005, 06:43
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