Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

when x< 0 : -x=3x-2 --> x = 1/2 , this is not a valid solution since we assumed x<0 therefore the soulution is invalid. when x>0 then x=3x-2 ---> x = 1 , this is a valid solution since we assumed that x > 0 , therefore Conditon B gives us a unique answer i.e. x= 1. Hence the answer is B.

i dont think that we need a condition " x must be an integer to get the answer B because statement 1 is surely not sufficient. statement 2 could be case first: if x> 0 so x is 1 case secondL if x< so so x is 1/2 . this case should be eliminated becos x must be negative so if x=1/2 this case will be deleted.... thus x=1

You are missing an important point - let me explain.

We all know that if we have mods, we take two cases - positive and negative - and then solve the equation. The point is - why do we do that? If you remember, this is how we define mods

|x| = x if x is positive and -x if x is negative

So basically, |x| takes different forms depending on whether x is positive or negative. When I want to solve |x|=3x-2, I can't solve with |x|.

So I split it into two cases: Case 1: x is positive I get x = 3x - 2 x = 1 I accept this value of x since x has to be +ve and satisfy given equation. It does both. Case 2: x is negative -x = 3x - 2 x = 1/2 I reject this value since x should be negative for the equation to look like this. So x can only take 1 value i.e. x = 1.

Remember, when you split |x| into two cases, you have to check that the value you get lies in the region in which you are expecting it to lie.
_________________

St2: X>0 X= 3x-2 -2x= -2 X =1 .. check if it satifies the equation |1| = 3(1)-2 = 1 ... satisfies

X<0 -x = 3x-2 -4x = -2 x= 1/2 again check if satisfies the equation |1/2| = 3(1/2)- 2 = -1/2 ... doesnt satisfy the equation Hence X =1

Answer has to B . I dont think that the question requires to say that X is an integer. only trick/tip here is : whenever there is Mod or Inequality , check the value whether it satifies the equation.

Now in option B people are confused whether 1/2 can be a value of the x or not But people ....try putting x=1/2 in the option B equation .... l x l = 3x-2 therefore l 1/2 l = 3*1/2 -2 here l 1/2 l will be +ve ...i.e. 1/2 therefore 1/2 = 3/2 - 2 = (3-4)/2 hence 1/2 = - 1/2 ...which is not possible

similarly we even take x as -1/2 then also the resulting values come as 1/2 = - 7/2 ...again unequal ....

in case if x is negative then we cannot say -x=3x-2 we should say -x= -3x -2 2x=-2 so x= -1

In case x is negative, 3x does not change to -3x. When we write 'x', the negative sign is already included. But when x is negative, |x| becomes -x. The reason is that |x| can never be negative. If x is negative, -x makes it positive. e.g. If x = -4 |x| = |-4| = 4 which is actually -x = -(-4) = 4 Hence |x| = -x when x is negative. When x is positive, |x| = x
_________________

"I reject this value since x should be negative for the equation to look like this. So x can only take 1 value i.e. x = 1."

im sorry but could you please explaine why you reject 1/2... its also positive as 1

Let me highlight the main points: |x| = x if x is positive and [highlight]|x| = -x if x is negative[/highlight] (As explained in the reply above)

Case 1: x is positive |x|=3x-2 becomes x=3x-2 When I solve this, I get x = 1. This is acceptable since here I am working on the case where x is positive.

[highlight]Case 2: x is negative[/highlight] [highlight]|x|[/highlight]=3x-2 becomes [highlight]-x[/highlight]= 3x - 2 Now I solve and get a value of x. This value will be acceptable only if it is negative since I am working on the case where x is negative. But when I solve, I get x = 1/2. It is not negative so I reject it.

To test, try and put x = 1 in |x|=3x-2 It satisfies.

Put x = 1/2 in |x|=3x-2 It doesn't satisfy.
_________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

After days of waiting, sharing the tension with other applicants in forums, coming up with different theories about invites patterns, and, overall, refreshing my inbox every five minutes to...

I was totally freaking out. Apparently, most of the HBS invites were already sent and I didn’t get one. However, there are still some to come out on...

In early 2012, when I was working as a biomedical researcher at the National Institutes of Health , I decided that I wanted to get an MBA and make the...