Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
My mistake, a=2/7 b but shouldnтАЩt тАЬbтАЭ be 7 for a to be less than 10 Can you elaborate more about your answer? Thanks
I think Statement (1) is sufficient because 27 is the only such integer. I tried to find solution for 3 and 4 digit numbers before posting and wasn't able to come up with anything. In fact, I would hit dead end after two iterations.
IMO, this is a really bad question. Whoever generated it. One must know something so whacky as this to solve the problem. But I give props to sarnia for taking the right approach in solving it.
Case 1: X cannot be a in single digits. Obviously.
Case 2: Say x has 2 digits, then 10a+b=3(a+b)=>a/b=2/7. Since a and b have to be single digits and not equal to 0, the only option is a=2,b=7.
Case 3: Say x has 3 digits, the maximum value can be 999, sum of digits = 27. Multiply with 3 to get 81. Even the maximum of the sum will not get near the minimum of 3 digit number 100. Therefore X cannot be a 3 digit number.
The logic in Case 3 can be extended for numbers with more than 2 digits (4,5 etc.). Therefore the answer is A.