two methods here.
1. using the solutions here. x= -3/2 and x= 2/7 are solutions.
check for the regions
a. x<-3/2, b. -3/2<x<2/7 and c. x>2/7
values are a -(2x+3) > (7x-2) giving x <-1/9 hence not a solution.
b (2x+3) > (7x-2) giving x < 1 a solution.
c (2x+3) > -(7x-2) giving x>-1/9 hence the solution is -1/9 < x < 1
2. squaring both sides
(2x+3) ^2 > (7x-2)^2
gives 9x^2 -8x - 1 > 0 giving solution -1/9 < x < 1.
Hence C you can use whichever you are comfortable with.
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