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When 15n is divided by 6, the remainder is x. Simplyfing the equation 15 * / 6 results in 5n/2 and also states that x is the remainder.
When a number is divided by 2, the reaminder can be 0 thru n-1 which means in our case x can be either 0 or 1. Now the question is to find the value or X. In 5n/2, 5 is not divisible by 2. So the value of x depends on whether n is even(in which case x = 0) or n is odd(in which case x = 1).
Clue 1 When n is divided by 2, remainder is 0. Clearly n is even and hence x is zero. Sufficient. Clue 2 When n is divided by 3, remainder is 0. Here n can be odd(for ex - 9) or even(for ex - 6) So x can be 1 or 1. Not sufficient.
Ans = A
Re: Divisibility/ Remainders
07 Oct 2009, 13:55