When 26 is divided by K, the remainder is K-2. K = ? (1)

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When 26 is divided by K, the remainder is K-2. K = ? (1) [#permalink]

20 Jun 2008, 01:20

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When 26 is divided by K, the remainder is K-2. K = ?
(1) K>5
(2) K<10

My approach is to plug in numbers and find out the solution. i m posting it here so as to know a logical way of solving it(i dont want to solve it by plugging in numbers)

statement 1 we are given that k>5, so K can be 7,or 14.so insufficent
statement 2 k can be 4 or 7.so insufficent

both statements put together we know that k can be 7 only

Comments please
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Re: DS question [#permalink]

20 Jun 2008, 01:30

26 = x*k + (K-2)
28 = (x+1)*K

it means that 28 is divisible by K
Possible values of K 2,4,7,14
now k can not be 2 as K-2 will become 0 and 26 will also be divisible by K.

From statement 1, k = 7,14
From statement 2, K = 5,7

The answer is C and we havent plugged values.....

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Re: DS question [#permalink]

20 Jun 2008, 01:36

durgesh79 wrote:

Thanks Durgesh

Understood this
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Re: DS question [#permalink] 20 Jun 2008, 01:36

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When 26 is divided by K, the remainder is K-2. K = ? (1)

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When 26 is divided by K, the remainder is K-2. K = ? (1)

When 26 is divided by K, the remainder is K-2. K = ? (1)

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