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# when a certain tree was first planted, it was 4 feet tall,

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when a certain tree was first planted, it was 4 feet tall, [#permalink]  12 Sep 2008, 17:11
when a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?

3/10
2/5
1/2
2/3
6/5

seems pretty simple but can't get the correct answer..........
Manager
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Re: work problem.. [#permalink]  12 Sep 2008, 17:28
lets the tree increase x feet every year..so at the end of 6 years the height will be 4+6x

so, 4 +6x = 6/5*( 4+ 4x) => x=2/3

6/5 becasue it is 1/5th taller
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Re: work problem.. [#permalink]  12 Sep 2008, 18:55
ssandeepan wrote:
lets the tree increase x feet every year..so at the end of 6 years the height will be 4+6x

so, 4 +6x = 6/5*( 4+ 4x) => x=2/3

6/5 becasue it is 1/5th taller

i dont understand where u came up with the equation 6/5(4+4x) would you please explain/?

thanks
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Re: work problem.. [#permalink]  12 Sep 2008, 19:27
Youngd8 wrote:
ssandeepan wrote:
lets the tree increase x feet every year..so at the end of 6 years the height will be 4+6x

so, 4 +6x = 6/5*( 4+ 4x) => x=2/3

6/5 becasue it is 1/5th taller

i dont understand where u came up with the equation 6/5(4+4x) would you please explain/?

thanks

(tree height @end of 4th year ) (1+1/5) = (tree height@ end of 6th year)

(4+4x)6/5= 4+6x
x=2/3
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Re: work problem..   [#permalink] 12 Sep 2008, 19:27
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# when a certain tree was first planted, it was 4 feet tall,

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