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# When a certain tree was planted it was 4 feet tall. The

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Manager
Joined: 23 Mar 2006
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When a certain tree was planted it was 4 feet tall. The [#permalink]  06 May 2006, 04:44
When a certain tree was planted it was 4 feet tall. The height incresed by a constant amount each year over the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the fourth year. By how many feet did the height of the tree increase each year?

3/10
2/5
1/2
2/3
6/5
Manager
Joined: 17 Jan 2006
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yup...looks like an error.
has anyone else come accross an error in GMAT prep
Manager
Joined: 23 Mar 2006
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I encountered some in my last test as well! What is the answer you get to this problem?
Manager
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Phew!
VP
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Re: GMAT Prep - Misprint? [#permalink]  06 May 2006, 06:00
Loner wrote:
When a certain tree was planted it was 4 feet tall. The height incresed by a constant amount each year over the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the fourth year. By how many feet did the height of the tree increase each year?

3/10
2/5
1/2
2/3
6/5

is there any problem. hmmm.... i donot see any

D. 4+6x = (4+4x) + 1/5(4+4x)
x=2/3 ft
Manager
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seeing your explanation.. now it makes sense.

i intepreted it as 4+6x = (4+4x) + 1/5, which is wrong

thanks!
Manager
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Hey prof,

You're right! Misinterpreted the question, just added 1/5 to 4+4x!!!
Manager
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Can you please also help me with these.

http://www.gmatclub.com/phpbb/viewtopic.php?t=29299
Manager
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Hey Prof: Can you explain something here.

I see that (4+6x) = the total height of the tree today

Then you set this equal to?

(4+4x), which equals end of 4th year?

+

1/5(4+4x), which is end of 6th year?

That doesn't seem to make sense to me, so I guess I'm not following...
Manager
Joined: 27 Mar 2006
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agree with 2/3...there doesnt seem to be a problem with the question
VP
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consultinghokie wrote:
Hey Prof: Can you explain something here.
I see that (4+6x) = the total height of the tree today
Then you set this equal to?
(4+4x), which equals end of 4th year?
+
1/5(4+4x), which is end of 6th year?
That doesn't seem to make sense to me, so I guess I'm not following...

height at the end of 6th yr = 4 + x+x+x+x+x+x = 4+6x
height at the end of 4th yr = 4 + x+x+x+x = 4+4x
height at the end of 6th yr = height at the end of 4th yr + 1/5(height at the end of 4th yr) = (4+4x) + 1/5 (4+4x)

solve it, x = 2/3
VP
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Yeah I get 2/3 also!

2x =1/5(4+4x)

Thus x =2/3
VP
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sm176811 wrote:
Yeah I get 2/3 also!

2x =1/5(4+4x). Thus x =2/3

good one............ lol.....
Senior Manager
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got 1/10 also I see now that they say 1/5 taller, not 1/5" taller
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