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Manager
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When a certain tree was planted it was 4 feet tall. The [#permalink]
 06 May 2006, 05:44
When a certain tree was planted it was 4 feet tall. The height incresed by a constant amount each year over the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the fourth year. By how many feet did the height of the tree increase each year?
3/10
2/5
1/2
2/3
6/5
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Manager
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yup...looks like an error.
has anyone else come accross an error in GMAT prep
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Manager
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I encountered some in my last test as well! What is the answer you get to this problem?
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Manager
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 Phew!
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Re: GMAT Prep - Misprint? [#permalink]
06 May 2006, 07:00
Loner wrote: When a certain tree was planted it was 4 feet tall. The height incresed by a constant amount each year over the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the fourth year. By how many feet did the height of the tree increase each year?
3/10
2/5
1/2
2/3
6/5
is there any problem. hmmm.... i donot see any 
D. 4+6x = (4+4x) + 1/5(4+4x)
x=2/3 ft
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hmm..good answer, i t was a reading error on my part.
seeing your explanation.. now it makes sense.
i intepreted it as 4+6x = (4+4x) + 1/5, which is wrong
thanks!
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Manager
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Hey prof,
You're right! Misinterpreted the question, just added 1/5 to 4+4x!!!
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Manager
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Hey Prof: Can you explain something here.
I see that (4+6x) = the total height of the tree today
Then you set this equal to?
(4+4x), which equals end of 4th year?
+
1/5(4+4x), which is end of 6th year?
That doesn't seem to make sense to me, so I guess I'm not following...
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Manager
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agree with 2/3...there doesnt seem to be a problem with the question 
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VP
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consultinghokie wrote: Hey Prof: Can you explain something here.
I see that (4+6x) = the total height of the tree today
Then you set this equal to?
(4+4x), which equals end of 4th year?
+
1/5(4+4x), which is end of 6th year?
That doesn't seem to make sense to me, so I guess I'm not following...
height at the end of 6th yr = 4 + x+x+x+x+x+x = 4+6x
height at the end of 4th yr = 4 + x+x+x+x = 4+4x
height at the end of 6th yr = height at the end of 4th yr + 1/5(height at the end of 4th yr) = (4+4x) + 1/5 (4+4x)
solve it, x = 2/3
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VP
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Yeah I get 2/3 also!
2x =1/5(4+4x)
Thus x =2/3
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VP
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sm176811 wrote: Yeah I get 2/3 also!
2x =1/5(4+4x). Thus x =2/3
good one............ lol.....
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Senior Manager
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got 1/10 also  I see now that they say 1/5 taller, not 1/5" taller
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