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When a cylindrical tank is filled with water at a rate of 22

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When a cylindrical tank is filled with water at a rate of 22 [#permalink] New post 18 Dec 2005, 01:16
00:00
A
B
C
D
E

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  5% (low)

Question Stats:

75% (01:02) correct 25% (00:00) wrong based on 4 sessions
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. Which of the following best approximates the radius of the tank in meters?

A. sqrt10/2
B. sqrt10
C. 4
D. 5
E. 10
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 [#permalink] New post 18 Dec 2005, 01:26
In 1 hr,

volume = 22 = pi (r^3)(0.7)

pi is 22/7 (approximately), so 22 = 22/7(r^3)(7/10)

22 = 22/10(r^3)
10 = r^3

So choice c,d, and e are out since 4^3, 5^3 and 10^3 are out greater than 10.

sqrt9 = 3, sqrt 16 = 4, so sqrt10 is going to be slightly above 3. So choice B is out, since r^3 = 10 * sqrt(10) which is going to be slightly above 30.

I pick A
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 [#permalink] New post 18 Dec 2005, 02:00
My choice too, but we are both wrong. MGMAT ranks this as a 600 level Q problem.
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Answer [#permalink] New post 18 Dec 2005, 04:10
Hello, I choose B, since

the amount of water that flows into the cyclindrical tank can be expressed as

22= 0,7 * r²* Pi, thus

220/7= r²* Pi, which is approx.

210/7=30= r²* Pi, since Pi equals 3,14 and 220 is slghtly above 30 we can estimate that

r²= 10,

which is B
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Re: Answer [#permalink] New post 18 Dec 2005, 08:43
Another vote for B. allabout's explanation is very clear.
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 [#permalink] New post 18 Dec 2005, 20:40
I made an error in calculation !! Sorry, the volume of the cylinder should be pi*r^2*h. I do not know why I put it down as pi*r^3^h and even went on to work out the problem. :oops:
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 [#permalink] New post 18 Dec 2005, 20:43
Here's my re-worked solution:

volume = 22 = pi (r^2)(0.7)

22 = 22/7 (7/10)(r^2)
10 = r^2
r = sqrt(10)

Ans: B
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Re: PS MGMAT 1-7 [#permalink] New post 18 Dec 2005, 22:36
GMATT73 wrote:
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. Which of the following best approximates the radius of the tank in meters?

A. sqrt10/2
B. sqrt10
C. 4
D. 5
E. 10


22 = PI r^2 * 0.7
22 = 22/7 * r^2 * 0.7
1= r^2/10
=> r= Sqrt(10) ----> B
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 [#permalink] New post 19 Dec 2005, 23:09
Yes, the trick to this problem is remembering that pi=22/7.

OA is B.
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 [#permalink] New post 20 Dec 2005, 14:33
obviously B

22 CM =Pi* r^2*h (balancing the volume)

22 CM = Pi*r^2*0.7

r= sqrt (22/0.7)*1/Pi BTW 22/7 = pi

r= sqrt10
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 [#permalink] New post 20 Dec 2005, 19:03
GMATT73 wrote:
My choice too, but we are both wrong. MGMAT ranks this as a 600 level Q problem.


I got B so I am a 600 level person. :cry:
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 [#permalink] New post 20 Dec 2005, 19:08
Bhai wrote:
GMATT73 wrote:
My choice too, but we are both wrong. MGMAT ranks this as a 600 level Q problem.


I got B so I am a 600 level person. :cry:


Since the OA is B, and you've answered B, it means you're too good for 600 level questions, nothing to be sad about yeah? :lol:
  [#permalink] 20 Dec 2005, 19:08
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