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when added 10X, the resulting figure is (5y+1) times of the

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VP
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when added 10X, the resulting figure is (5y+1) times of the [#permalink] New post 17 Feb 2005, 21:23
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when added 10X, the resulting figure is (5y+1) times of the original value. what is the original value in terms of x and y?
Manager
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 [#permalink] New post 17 Feb 2005, 21:34
according to my understanding :

z: original value

z+ 10x = (5y+1)z
10x-5yz=0

z = 2x/y
VP
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 [#permalink] New post 17 Feb 2005, 21:49
Same as above...
a+10x = 5ya + a
10x = 5ya ; a = 2x/y
Senior Manager
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 [#permalink] New post 18 Feb 2005, 08:49
2x/y
(same reasoning)
unless there is something missing in the question
  [#permalink] 18 Feb 2005, 08:49
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when added 10X, the resulting figure is (5y+1) times of the

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