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when added 10X, the resulting figure is (5y+1) times of the

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VP
Joined: 25 Nov 2004
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when added 10X, the resulting figure is (5y+1) times of the [#permalink]  17 Feb 2005, 21:23
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when added 10X, the resulting figure is (5y+1) times of the original value. what is the original value in terms of x and y?
Manager
Joined: 11 Jan 2005
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[#permalink]  17 Feb 2005, 21:34
according to my understanding :

z: original value

z+ 10x = (5y+1)z
10x-5yz=0

z = 2x/y
VP
Joined: 13 Jun 2004
Posts: 1122
Location: London, UK
Schools: Tuck'08
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Kudos [?]: 31 [0], given: 0

[#permalink]  17 Feb 2005, 21:49
Same as above...
a+10x = 5ya + a
10x = 5ya ; a = 2x/y
Manager
Joined: 15 Feb 2005
Posts: 247
Location: Rockville
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[#permalink]  18 Feb 2005, 08:49
2x/y
(same reasoning)
unless there is something missing in the question
[#permalink] 18 Feb 2005, 08:49
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when added 10X, the resulting figure is (5y+1) times of the

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