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When an object is dropped, the number of feet N that it

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When an object is dropped, the number of feet N that it [#permalink] New post 27 Apr 2006, 22:34
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When an object is dropped, the number of feet N that it falls is given by the formula N=1/2 gt^2, where t is the time in seconds since it was dropped and g is 32.2, if it takes 5 seconds for the object to reach the ground, how many feet does it fall?
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Re: PS Object [#permalink] New post 27 Apr 2006, 23:11
getzgetzu wrote:
When an object is dropped, the number of feet N that it falls is given by the formula N=1/2 gt^2, where t is the time in seconds since it was dropped and g is 32.2, if it takes 5 seconds for the object to reach the ground, how many feet does it fall?


isn't just

N= 1/2*32.2*(5^2)

N= 16.1*25 = 402.5
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 [#permalink] New post 28 Apr 2006, 01:22
getzgetzu wrote:
The OA is 144.9


could you double check your question, isn't 5 seconds or 3 seconds?
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 [#permalink] New post 28 Apr 2006, 01:39
I get 402.5 also!! How did u get 144.9! Unless probabaly the object is thrown up! Then the kinematics shud be different!

U need to break it up into two sections and then compute!
  [#permalink] 28 Apr 2006, 01:39
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When an object is dropped, the number of feet N that it

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