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When k! is written as m*10^n so that the last digit of [#permalink]
04 Oct 2006, 06:51
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When k! is written as m*10^n so that the last digit of integer m is not 0, the difference between the number of digits in m and the value of n is 5. If t is the number of possibilities there are the value of the integer k, then t+1=