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When n = 100x + 10y + z, function f is defined as f(n) =

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Director
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When n = 100x + 10y + z, function f is defined as f(n) = [#permalink]  06 Dec 2005, 06:56
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When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

(Answer choices not available)
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Re: PS - Function [#permalink]  06 Dec 2005, 07:16
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

(Answer choices not available)

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20
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Re: PS - Function [#permalink]  06 Dec 2005, 07:54
laxieqv wrote:
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

(Answer choices not available)

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20

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Director
Joined: 14 Sep 2005
Posts: 998
Location: South Korea
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Re: PS - Function [#permalink]  07 Dec 2005, 07:05
bewakoof wrote:
laxieqv wrote:
gamjatang wrote:
When n = 100x + 10y + z, function f is defined as f(n) = (2^x)(3^y)(5^z).

If f(v) = 9f(u), what is v minus u?

(Answer choices not available)

notice 9= 3^2 --> the only possible difference between f(v) and f(t) is of 3^y ....f(v) contains 3^(y+2) ...powers of 2 and 5 in both functions f() are the same

----> u= 100x+10y+z and v= 100x+10(y+2) +z
----> v-u= 10*2= 20

u are GENIIUS!

Yes she is.

The OA is 20.
_________________

Auge um Auge, Zahn um Zahn !

Manager
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[#permalink]  07 Dec 2005, 07:38
crap, I could never get that.
Would this be considered medium difficulty or hard?
Intern
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[#permalink]  08 Dec 2005, 11:04
Got 20 as well. Only way to increase 9 fold is using 3^2 which means y has increased by 2 and 10*2 = 20.
Director
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[#permalink]  09 Dec 2005, 09:38
stretchad wrote:
crap, I could never get that.
Would this be considered medium difficulty or hard?

I'd say, this question falls in the "super hard" category.
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Auge um Auge, Zahn um Zahn !

SVP
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[#permalink]  09 Dec 2005, 10:17
gamjatang wrote:
stretchad wrote:
crap, I could never get that.
Would this be considered medium difficulty or hard?

I'd say, this question falls in the "super hard" category.

Do you get this type of questions in the real test.
_________________

hey ya......

[#permalink] 09 Dec 2005, 10:17
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