When positive integer n is divided by 3, the remainder is 2; : DS Archive
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# When positive integer n is divided by 3, the remainder is 2;

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When positive integer n is divided by 3, the remainder is 2; [#permalink]

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18 Nov 2007, 08:06
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When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5

2) t is divisible 3
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18 Nov 2007, 11:33
gluon wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5
2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient.
2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15.
if nt is 2x3, r is 6.
if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.
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24 Nov 2007, 15:19
Himalayan wrote:
gluon wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5
2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient.
2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15.
if nt is 2x3, r is 6.
if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

17*9=153

153/15= 10 and r=3

7*9=63

63/15= 4 and r=3

Is that right?
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24 Nov 2007, 17:19
Himalayan wrote:
gluon wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5
2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient.
2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15.
if nt is 2x3, r is 6.
if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

same approach...but was taking a lot of time..guess need to plug in numbers
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24 Nov 2007, 20:20
hold on a second ... in the stem, we are told that when n is divided by 3, the remainder is 2

statement 1 tells us that n-2 is divisible by 5, i.e. n-2 = 5, 10, 15, 20, 25...

therefore, n=7,12,17,22,27 ...

but if we take these values of n and divide by 3, i dont get a remainder of 2

can someone point out where i went wrong in my logic ?
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25 Nov 2007, 00:35
GMAT TIGER wrote:
Deckard wrote:
Himalayan wrote:
gluon wrote:
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5
2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient.
2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15.
if nt is 2x3, r is 6.
if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

17*9=153

153/15= 10 and r=3

7*9=63

63/15= 4 and r=3

Is that right?

t cannot be 9.

Got it. I was too concentrated on the statements and I forgot to consider the text. Thanx.
Re: DS - remainder   [#permalink] 25 Nov 2007, 00:35
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