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When positive integer n is divided by 3, the remainder is 2; [#permalink]
18 Nov 2007, 08:06

00:00

A

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C

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Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 1 sessions

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

Re: DS - remainder [#permalink]
18 Nov 2007, 11:33

gluon wrote:

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5 2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient.
2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15.
if nt is 2x3, r is 6.
if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

Re: DS - remainder [#permalink]
24 Nov 2007, 15:19

Himalayan wrote:

gluon wrote:

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5 2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient. 2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15. if nt is 2x3, r is 6. if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

Re: DS - remainder [#permalink]
24 Nov 2007, 17:19

Himalayan wrote:

gluon wrote:

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5 2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient. 2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15. if nt is 2x3, r is 6. if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

same approach...but was taking a lot of time..guess need to plug in numbers

Re: DS - remainder [#permalink]
25 Nov 2007, 00:35

GMAT TIGER wrote:

Deckard wrote:

Himalayan wrote:

gluon wrote:

When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?

1) n – 2 is divisible by 5 2) t is divisible 3

i guess, an example/plugging numbers would be better:

1. n could be 2 or 17 or 32 etc. insufficient. 2. t could be 3, 18, 33, or so on. so also insuff.

togather we can conclude on the reminder of "nt" when it is divided by 15. if nt is 2x3, r is 6. if nt is 17x18, r is 6.

so C.

Note: when calculating reminder never do as under:

(17x18)/15 = (17x6)/5. so reminder is 2. its wrong because 17x18 is already divided by 3. to get the proper reminder of nt, 2 should be multiplied by 3. so the reminder is 6.

17*9=153

153/15= 10 and r=3

7*9=63

63/15= 4 and r=3

Is that right?

t cannot be 9.

Got it. I was too concentrated on the statements and I forgot to consider the text. Thanx.

gmatclubot

Re: DS - remainder
[#permalink]
25 Nov 2007, 00:35

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