Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

When positive integer n is divided by 3 the remainder is 2; [#permalink]
11 May 2008, 18:37

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

1) n-2 is divisible by 5 2) t is divisible by 3 _________________

Chinese Democracy is misunderstood...at your nearest BestBuy.

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

1) n-2 is divisible by 5 2) t is divisible by 3

E.

Try values: 17, 27, and 32 for N. And anything divisible by 3 for t. Id start w/ 3.

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

1) n-2 is divisible by 5 2) t is divisible by 3

E.

Try values: 17, 27, and 32 for N. And anything divisible by 3 for t. Id start w/ 3.

27 is divisible by 3 and therefore cannot be N.

Plugging n=17 and t=3 -> tn=51 -> 51/15 -> r=6 Plugging n=32 and t=3 -> tn=96 -> 96/15 -> r=6 Plugging n=17 and t=18 -> tn=306 -> 306/15 -> r=6

OA is C.

But plugging numbers like this takes way longer than 2-3 min since you don't have many options to deal with simple numbers. Does anyone have a shorter solution? _________________

Chinese Democracy is misunderstood...at your nearest BestBuy.

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

1) n-2 is divisible by 5 2) t is divisible by 3

E.

Try values: 17, 27, and 32 for N. And anything divisible by 3 for t. Id start w/ 3.

27 is divisible by 3 and therefore cannot be N.

Plugging n=17 and t=3 -> tn=51 -> 51/15 -> r=6 Plugging n=32 and t=3 -> tn=96 -> 96/15 -> r=6 Plugging n=17 and t=18 -> tn=306 -> 306/15 -> r=6

OA is C.

But plugging numbers like this takes way longer than 2-3 min since you don't have many options to deal with simple numbers. Does anyone have a shorter solution?

arghhh... serves me right for doing this in my head

I wonder if my approach was too basic and simple...

I plugged in n=5, t=8

Remainder of tn/15= 10

plugged in n and t into statements (1) & (2) and found both insufficient.

I still got E as the answer but is there a step I'm missing? (Even if answer is correct, if the approach is incorrect it doesnt help)

chineseburned wrote:

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

When positive integer n is divided by 3 the remainder is 2; and when positive integer t is divided by 5 the remainder is 3. What is the remainder when the product tn is divided by 15?

1) n-2 is divisible by 5 2) t is divisible by 3

Hi,

n=3x+2-----------(1) t=5y+3-----------(2)

Statement 1: arranging (1) n-2=3x this means 3x is divisible by 5 let 3x=3*5*a=15a equation (1) is now n=15a+2 not suff

Statement 2: (2)is divisible by 3 means 5y is divisible by 3 so let 5y=3*5*b=15b

eq (2) now is t=15b+3 not suff

combining nt=15a+2*15b+3

all terms except 6 is divisible by 6 so remainder is 6