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Re: When positive integer N is divided by positive integer P, the quotient [#permalink]
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Here we go:


Dividend = Divisor * quotient + remainder.

Put in the values -> Solve the two equations.


option A is correct.
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Re: When positive integer N is divided by positive integer P, the quotient [#permalink]
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Bunuel wrote:
When positive integer N is divided by positive integer P, the quotient is 18, with a remainder of 7. When N is divided by (P + 2), the quotient is 15 and the remainder is 1. What is the value of N?

A. 151
B. 331
C. 511
D. 691
E. 871

Kudos for a correct solution.


MAGOOSH OFFICIAL SOLUTION:

Use the rule dividend = (integer quotient)*(divisor) + remainder to translate each sentence.

The first sentence becomes N = 18P + 7. The second equation becomes N = (P + 2)*15 + 1, which simplifies to N = 15P + 31. These are ordinary simultaneous equations (https://magoosh.com/gmat/2012/gmat-quant ... variables/). Since they both equal N already, let’s set them equal and solve for P.
18P + 7 = 15P + 31
3P + 7 = 31
3P = 24
P = 8

Now that we know P = 8, we can just plug in. The product 15*8 is particularly easy to do, without a calculator, by using the “doubling and halving” trick. Double 15 to get 30, and take half of 8 to get 4 —- 15*8 = 30*4 = 120. So
N = 15(8) + 31 = 120 + 31 = 151
N = 151, answer = A.
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Re: When positive integer N is divided by positive integer P, the quotient [#permalink]
Hello,

The formula Says: Dividend=Divisor*Quotient + remainder, how we can flip this formula to get the answer.
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Re: When positive integer N is divided by positive integer P, the quotient [#permalink]
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