When positive integer x is divided by positive integer y,

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When positive integer x is divided by positive integer y, [#permalink]

20 Nov 2007, 19:56

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When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?

A. 96

B. 75

C. 48

D. 25

E. 12

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20 Nov 2007, 20:31

Hmm, I'm stuck between B and D

int = x = 96.12 * y
X will be integer when 96.12 is multiplied by 75 or 25
What's next?...

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20 Nov 2007, 21:02

Its B

96.12 = 96 + 0.12
Therefore remainder 9 when divided by Y = 0.12
9/Y = 0.12.
Y = 75

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20 Nov 2007, 21:15

gk2k2 wrote:

Therefore remainder 9 when divided by Y = 0.12

I beg your pardon, gk2k2, but could you please explain this (I can't get it)? Is it a kind of properties?

UPD: Sorry, I got it =)

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21 Nov 2007, 15:14

x/y = 96.12 = 96 + 12/100 = 96 + 3/25

Now to get remainder 9, you must represent it as:

96 + 9/75 so that (96* 75 + 9) when divided by 75 will leave remainder 9. Therefore answer would be 75.

If it were 25, the remainder would be 3.

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21 Nov 2007, 20:19

abhishakes2001 wrote:

super work !
thats the way to do this .
break the fraction in terms of ny + R

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Re: PS--- Set#2 Q2 [#permalink]

21 Nov 2007, 22:19

humtum0 wrote:

When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?

A. 96

B. 75

C. 48

D. 25

E. 12

B, 75.

x = 96.12y + r (given)
x/y = 96.12 + r/y (where r/y represents the decimal portion of the quotient)
r/y = 9/y = .12
y = 9/.12 = 75

Re: PS--- Set#2 Q2 [#permalink] 21 Nov 2007, 22:19

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When positive integer x is divided by positive integer y,

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When positive integer x is divided by positive integer y,

When positive integer x is divided by positive integer y,

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