When the integer x is divided by the integer y

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When the integer x is divided by the integer y [#permalink]

19 Jan 2012, 17:16

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Question Stats:

30% (01:53) correct

70% (01:08) wrong

based on 4 sessions

When the integer x is divided by the integer y, the remainder is 60. Which of the following is a possible value of the quotient x/y?

I. 15.15
II.18.16
III. 17.17

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I and III only

I don't have a clue how this will be solved. Can someone please help? Unfortunately, I don't have an OA either.

[Reveal] Spoiler: OA

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Re: Value of Quotient x/y [#permalink]

19 Jan 2012, 19:12

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enigma123 wrote:

When the integer x is divided by the integer y, the remainder is 60. Which of the following is a possible value of the quotient x/y?
I. 15.15
II.18.16
III. 17.17

(A) I only
(B) II only
(C) III only
(D) I and II only
(E) I and III only

I don't have a clue how this will be solved. Can someone please help? Unfortunately, I don't have an OA either.

"x is divided by the integer y, the remainder is 60" --> x=qy+60 --> or \frac{x}{y}=q+\frac{60}{y}, so basically \frac{60}{y} is a decimal portion of \frac{x}{y}.

For example: \frac{x}{y}=15.15 means that \frac{x}{y}=15+0.15=15+\frac{60}{y}

Let's look at the options:
I. If \frac{x}{y}=15.15 then \frac{60}{y}=0.15 and y=400=integer, which is possible;
II. If \frac{x}{y}=18.18 then \frac{60}{y}=0.18 and y=375=integer, which is possible;
III. If \frac{x}{y}=17.17 then \frac{60}{y}=0.17 and y=\frac{6000}{17}\neq{integer}, which is not possible as y must be an integer.

Answer: D.
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Re: Value of Quotient x/y [#permalink] 19 Jan 2012, 19:12

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When the integer x is divided by the integer y

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When the integer x is divided by the integer y

When the integer x is divided by the integer y

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