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Check your solution please! The answer is E. 65 doesn't satisfy condition 1/. It is rather 55 and 55 does work, which means that when 55 is divided by 4, the remainder is 3. Since this is not the case for 25, there is not enough information. Otherwise you did a very good job, fellow!

Quote:

How you perceive people and things will set the pace of your journey and dictate your reality!

_________________

Dakar Azu is The GMAT Doctor. Dakar is an experienced GMAT teacher who can be reached at http://700gmatclub.com. He prepares aspiring business students thoroughly to get them well over the GMAT 700-score hurdle through his online GMAT courses.

Last edited by TheGMATDoctor on 13 Jul 2010, 13:09, edited 2 times in total.

1) When x/3 is divided by 2, the remainder is 1. It means that x is divisible by 3 because x/3 has to be an integer. So, x=3, r=3 x=9, r=1 insufficient

2) x is divisible by 5.

So, x=5, r=1 x=15, r=3 insufficient

1)&2) write out x that satisfy 1st condition and find two the closest numbers that satisfy 2nd condition also:

x=3,9,15,21,27,43,49,55

So, x=15, r=3 x=55, r=3 sufficient

TheGMATDoctor wrote:

The answer is E.

Give two examples that satisfy both conditions and give different remainders.
_________________

25 is not divisible by 3 and therefore first condition is not satisfied or maybe you know what is remainder when 8.333333 is divided by 2
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25 is not divisible by 3 and therefore first condition is not satisfied or maybe you know what is remainder when 8.333333 is divided by 2

hey walker, statement 1 does not say that x has to be divisible by 3, it say x/3 divide by 2 ---> x/6. This is another typical question by chineseburn, where the wording is unnecessary complicated and designed to play "gotcha".

In my earlier post above, I assumed that the integer x is being divided by 6. (Otherwise you must assume that x/3 is an integer). Indeed, the division algorithm (actually a theorem that relates to all integers positive, zero and negative with the constraint that d ≠ 0 ) states that for two integers a and d, with d ≠ 0, there are unique integers q and r such that a = qd + r and 0 ≤ r < |d| , The integer -q is called the quotient - r is called the remainder -d is called the divisor -a is called the dividend This question needs to be more clear as it is the case in the GMAT. The set of "qualified" integers you get will depend on your choice of "x/3" or "x/6" since an integer can be divisible by 3 without being divisible by 6. If you choose to go with "x/6" then you'll have the "qualified" integer 55. 55 is divisible by 5 and when you divide 55 by 6 the remainder is 1. So the two conditions are satisfied. Finally when you divide 55 by 4 the remainder is 3. The "qualified'' integer 25 will give a remainder of 1 when divided by 4. Yet, no matter what option you go with, the answer will still be E. Very nice discussion overall!

Quote:

How you perceive people and things will set the pace of your journey and dictate your reality!

_________________

Dakar Azu is The GMAT Doctor. Dakar is an experienced GMAT teacher who can be reached at http://700gmatclub.com. He prepares aspiring business students thoroughly to get them well over the GMAT 700-score hurdle through his online GMAT courses.