When the positive integer x is divided by 9, the remainder

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When the positive integer x is divided by 9, the remainder [#permalink]

22 Nov 2007, 18:04

When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?
0

1

3

4

6

I could use the plug in no. approach but it's too time consuming. Please help.
thanks
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Re: MGMT - Remainder [#permalink]

22 Nov 2007, 18:11

alimad wrote:

X=9K+5

3X=3(9K+5)

then

(27K+15)/9
3K+15/9
15/9 ends with remainder 6.

E
also plug any number into K to test

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Re: MGMT - Remainder [#permalink]

22 Nov 2007, 18:32

alimad wrote:

6
Plugging is simple here.

x = 9k + 5
for k =1 x = 14
3x = 42 . Divide by 9 , you get remainder 6.
Same with k=2 and other k's

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Re: MGMT - Remainder [#permalink]

22 Nov 2007, 20:50

alimad wrote:

Answer is 6

lets say the quotient is y.

So from the first part 9y+ 5 = x

so 3x = 27y + 15(remainder)

since 15 when divided by 9 gives you 6....

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[#permalink]

01 Dec 2007, 22:03

Is it better to plug in on remainder questions?

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Re: MGMT - Remainder [#permalink]

02 Dec 2007, 03:40

[quote="alimad"]When the positive integer x is divided by 9, the remainder is 5. What is the remainder when 3x is divided by 9?
0

1

3

4

6

x= 9k+5 ie: 3x = 27k+15, 27k+15 / 9 = a reminder of 15-9 = 6

Re: MGMT - Remainder [#permalink] 02 Dec 2007, 03:40

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When the positive integer x is divided by 9, the remainder

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When the positive integer x is divided by 9, the remainder

When the positive integer x is divided by 9, the remainder

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