When the price of oranges is lowered by 40%, 4 more oranges : GMAT Problem Solving (PS)
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# When the price of oranges is lowered by 40%, 4 more oranges

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Manager
Joined: 15 Apr 2012
Posts: 93
Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GMAT 2: Q V
GPA: 3.56
Followers: 0

Kudos [?]: 40 [0], given: 134

When the price of oranges is lowered by 40%, 4 more oranges [#permalink]

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08 Jul 2012, 05:19
00:00

Difficulty:

25% (medium)

Question Stats:

70% (02:51) correct 30% (01:08) wrong based on 43 sessions

When the price of oranges is lowered by 40%, 4 more oranges can be purchased for $12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price? (A) 8 (B) 12 (C) 16 (D) 20 (E) 24 [Reveal] Spoiler: OA Last edited by Bunuel on 08 Jul 2012, 05:22, edited 1 time in total. Edited the question. Math Expert Joined: 02 Sep 2009 Posts: 36609 Followers: 7099 Kudos [?]: 93523 [1] , given: 10568 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 08 Jul 2012, 05:33 1 This post received KUDOS Expert's post farukqmul wrote: When the price of oranges is lowered by 40%, 4 more oranges can be purchased for$12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price?

(A) 8
(B) 12
(C) 16
(D) 20
(E) 24

Say $$x$$ is the original price of an orange, then:

$$xn=12$$;
and
$$0.6x*(n+4)=12$$ --> $$x(n+4)=20$$ --> $$xn+4x=20$$ --> $$12+4x=20$$ --> $$x=2$$.

So, for 24 dollars 24/2=12 oranges can be purchased at the original price of $2. Answer: B. _________________ Intern Joined: 26 May 2012 Posts: 25 Followers: 2 Kudos [?]: 15 [0], given: 10 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 15 Jul 2012, 02:22 Bunuel wrote: farukqmul wrote: When the price of oranges is lowered by 40%, 4 more oranges can be purchased for$12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price?

(A) 8
(B) 12
(C) 16
(D) 20
(E) 24

Say $$x$$ is the original price of an orange, then:

$$xn=12$$;
and
$$0.6x*(n+4)=12$$ --> $$x(n+4)=20$$ --> $$xn+4x=20$$ --> $$12+4x=20$$ --> $$x=2$$.

So, for 24 dollars 24/2=12 oranges can be purchased at the original price of $2. Answer: B. are there any other ways? Senior Manager Status: Exam scheduled!! Joined: 05 Sep 2016 Posts: 411 Location: United States (WI) Concentration: Marketing, Technology WE: Other (Law) Followers: 3 Kudos [?]: 13 [0], given: 245 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 22 Oct 2016, 11:32 Set up: 12/p = x 12/0.60 = x+4 Manipulate and plug the first equation into the second --> you'll find p =$2

Thus $24/$2 per orange = 12 oranges
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Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink]

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22 Oct 2016, 17:22
farukqmul wrote:
When the price of oranges is lowered by 40%, 4 more oranges can be purchased for $12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price? (A) 8 (B) 12 (C) 16 (D) 20 (E) 24 let r=number of oranges purchased originally [12/(r+4)]/(12/r)=.6 r/(r+4)=.6 r=6 oranges$12/6=$2 per orange$24/\$2=12 oranges
B
Re: When the price of oranges is lowered by 40%, 4 more oranges   [#permalink] 22 Oct 2016, 17:22
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