vr4indian wrote:

When William received 10x coins, he then had 5y + 1 times as many coins as he had originally. In terms of x and y, how many coins did William have originally?

A) 10x(5y + 1)

B) (5y+1)/10x

C) 2x/y

D) 10/(5y + 1)

E) None of the above

i got consufed when this example comes in exam..... had no idea how to solve

Say William had C coins initially, he received 10x more coins. So totally C + 10x. The question says after he received 10x coins he had 5y+1

TIMES as many coins he had originally (originally he had C coins). Times means multiplication, So he had C(5y+1) coins.

so C + 10x = c(5y+1) = 5yC + C

C - C - 5yC = -10x

5yC = 10x

C = 2x/y

The key in these problems is read EACH and EVERY word carefully and converting the words into equations. I agree that it gets really confusing at times. It pays to spend a bit more time in understanding the question properly in word translation problems.

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