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Re: Which is the least number that must be subtracted from 1856 so that [#permalink]
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urfrndniks wrote:
Bunuel

I solved this with POE, subtracting each option from the original number and dividing it by 7, 12, 16. Solved it under 2 mins though.
A) 1856 - 137 = 1719 ; 1719/7 gives remainder 4 but dividing by 12 it fails, leave it
B) 1856 - 1361 = 495 ; 495/7 fails remainder is 5, leave it
C) 1856 - 140 = 1716; 1716/7 , fails remainder is not 4
D) 1856 - 157 = 1699; 1699/7, fails remainder is not 4
E) 1856-172 = 1684; dividing by all three 7, 12 and 16 gives remainder 4 - CORRECT

Is this approach suitable?

______________
Yes, that;s correct.
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Re: Which is the least number that must be subtracted from 1856 so that [#permalink]
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Let X be the number

1856 - X =336Q + 4

X = 1852 - 336Q

To minimize X, maximize Q

Max. value of Q = 5

So Min. value of X = 1852 - 336*5 = 172
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Re: Which is the least number that must be subtracted from 1856 so that [#permalink]
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