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Which of the following could be the median of a set consisti

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Which of the following could be the median of a set consisti [#permalink]

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22 Feb 2010, 21:48
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Which of the following could be the median of a set consisting of 6 different primes?

A. 2
B. 3
C. 9.5
D. 12.5
E. 39

[Reveal] Spoiler:
The answer is E, however can any one please explain this problem for me. Why it is 39:?:
[Reveal] Spoiler: OA

Last edited by Narenn on 06 Sep 2013, 06:14, edited 1 time in total.
Always put OA in the spoiler.
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22 Feb 2010, 22:45
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median of a set containing 6 different primes
median will be average of 3rd and 4th prime.
All prime greater than 2 are odd. So 3th and 4th primes are odd and their sum will be even and the median will be an integer. 3rd prime will be greater than 2 or 3(first 2 primes)

E
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22 Feb 2010, 22:53

( Why I am confused is as per the rule stated, sum of the odd numbers is even, however 39 is not even)..
Correct me if I am wrong

Thanks Again
Divakar KN
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23 Feb 2010, 03:44
divakarbio7 wrote:

( Why I am confused is as per the rule stated, sum of the odd numbers is even, however 39 is not even)..
Correct me if I am wrong

Thanks Again
Divakar KN

The median is calculated as the average of the two middle numbers. If the sum of the two numbers is even, average of those numbers can be even or odd. In this case the median is an odd number. Hence 39.
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23 Feb 2010, 08:16
divakarbio7 wrote:

( Why I am confused is as per the rule stated, sum of the odd numbers is even, however 39 is not even)..
Correct me if I am wrong

Thanks Again
Divakar KN

median is average of the middle 2 numbers(if the number of the items is even). sum of even, so the median will definitely be integer.

if another choice is 40, then i belive we got to pick up the numbers to see which one is the correct median.
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23 Feb 2010, 20:59
divakarbio7 wrote:

( Why I am confused is as per the rule stated, sum of the odd numbers is even, however 39 is not even)..
Correct me if I am wrong

Thanks Again
Divakar KN

odd+odd is even and even divided by 2 is always an integer.
Also it can't be 2 or 3 as all primes numbers are different.
Hence best possible choices is 39.
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30 Mar 2010, 21:13
Which of the following could be the median of a set consisting of 6 different primes?

A> 2
B> 3
C> 9.5
D> 12.5
E> 39

Answer says 39, however i am unable to understand this....
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30 Mar 2010, 21:20
Is this the correct Reasoning?

A> 2 - first prime, hence cant be a median
B> 3 - this option is out, because 3 is not a prime number
Option C & D - 9.5 & 12.5 - cant be the median because in 6 different prime the average for median shouldnt be a decimal (odd+ odd = even) so these options are out

E> 39 - only option left out is this - so it should be the answer!!!!!
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30 Mar 2010, 21:34
divakarbio7 wrote:
Is this the correct Reasoning?

A> 2 - first prime, hence cant be a median
B> 3 - this option is out, because 3 is not a prime number
Option C & D - 9.5 & 12.5 - cant be the median because in 6 different prime the average for median shouldnt be a decimal (odd+ odd = even) so these options are out

E> 39 - only option left out is this - so it should be the answer!!!!!

Approach is correct. Some modification to your explanation:
A: 2 - first prime, hence cant be a median
B: 3 - Second prime, hence cant be a median
C & D: 9.5 & 12.5 - cannot be the median because in case of 6 different prime the average of two odd numbers cannot be decimal.
E: 39 - only option left out is this - so it should be the answer
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01 Apr 2010, 04:59
Hi ,

Thank you for the explanation.

Have 2 more questions:
what is the value of n in the list k, n, 12, 6, 17?
a> k< n
b> The median of the numbers in the list is 10

What is the median number of employees per project for the projects at company Z?
a> 25 percent of the projects at company Z have 4 or more employees assigned to each project
b> 35 percent of the projects at company Z have 2 or fewer employees assigned to each project.

i am not able to understand the logic for 2nd problem..answer says C - but note sure why?
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05 Oct 2010, 03:22
Please post the official explaination E seems to be ambiguis as 39 is not average of any two primes
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05 Oct 2010, 03:41
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prashantbacchewar wrote:
Please post the official explaination E seems to be ambiguis as 39 is not average of any two primes

Actually it is: 37 and 41 --> average = 39.
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Which of the following could be the median [#permalink]

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14 Aug 2013, 02:33
Which of the following could be the median of a set consisting of 6 different primes?
(A) 2 (B) 3 (C) 9.5 (D) 12.5 (E) 39

Can somebody plz explain how to proceed.

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Re: Which of the following could be the median [#permalink]

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14 Aug 2013, 02:37
Countdown wrote:
Which of the following could be the median of a set consisting of 6 different primes?
(A) 2 (B) 3 (C) 9.5 (D) 12.5 (E) 39

Can somebody plz explain how to proceed.

Median of 6 primes :$$\frac{odd+odd}{2}$$ = Integer. Options C and D are discarded immediately.

Options A and B can never be the median of 6 primes.

Only option E remains.
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Re: Which of the following could be the median [#permalink]

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14 Aug 2013, 02:43
Countdown wrote:
Which of the following could be the median of a set consisting of 6 different primes?
(A) 2 (B) 3 (C) 9.5 (D) 12.5 (E) 39

Can somebody plz explain how to proceed.

Merging similar topics. Please refer to the solutions above.
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Re: Which of the following could be the median of a set consisti [#permalink]

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19 Apr 2014, 22:47
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This can be done by hit and trial.

(A) 2 (B) 3 (C) 9.5 (D) 12.5 (E) 39

Since all primes should be different, we can take one set as below:

2..3..5..7..11..13

Median (5+7)/2 = 6

Hence, median cannot be less than 6, so reject options A and B

Since primes are odd and the number of terms is 6. So, we will always have median in the below form

(odd+odd)/2 = Even/2 = Integer.

Reject (C) and (D)

Hence (E)
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Re: Which of the following could be the median of a set consisti [#permalink]

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22 Dec 2015, 11:37
Countdown wrote:
Which of the following could be the median of a set consisting of 6 different primes?
(A) 2 (B) 3 (C) 9.5 (D) 12.5 (E) 39

Can somebody plz explain how to proceed.

let the consecutive primes be a,b,c,d,e,f
So the median will be (c+d)/2

Looking options we have to find 2*(any options) as sum of two consecutive primes.

becoz median here is avg. of two primes.

1) 2 (ie 2*2=4) so 4 cannot be the sum of middle two primes in a set of six consecutive primes.
2) 3 (3*2=6) same as option 1.
3)9.5(2*9.5=19) so sum can be 17+2 but 17 and 2 were not consecutive.
4)12.5 (2*12.5=25) same as option 3 ie we cannot find any two consecutive primes adding to 25.
5)39 (2*39=78) so here we find 78=37+41 are the two consecutive primes so the set is{29,31,37,41,43,47}

so E is our ans.
Re: Which of the following could be the median of a set consisti   [#permalink] 22 Dec 2015, 11:37
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