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# Which of the following expressions is defined for all

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Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 21 [0], given: 0

Which of the following expressions is defined for all [#permalink]  29 Oct 2006, 09:28
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0% (00:00) correct 0% (00:00) wrong based on 1 sessions
Which of the following expressions is defined for all integer values of z, such that z^2<9?

I. (z+1)/ z

II. (z-4)/ z^2-4z+4

III. 18/ z^2 -4z-5

a. none
b. I only
c. II only
d. III only
e. II and III only

... I'm not sure what the question is asking for... This is from Kaplan.
_________________

Impossible is nothing

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Manager
Joined: 28 Oct 2006
Posts: 82
Followers: 1

Kudos [?]: 0 [0], given: 0

d. III only

z, such that z^2<9 implies that z can be -2, -1, 0, 1 and 2

I and II are not defined for z=0 and z=-2 as the denominator = 0
III is defined for all the above mentioned values of z

hope i didnt screw it up somewhere....
Senior Manager
Joined: 23 May 2005
Posts: 266
Location: Sing/ HK
Followers: 1

Kudos [?]: 21 [0], given: 0

I think III is also not defined. If z=-1, denominator becomes 0.

so maybe the answer is a. none

sorry, i don't have the oa for this. another kaplan question here.
_________________

Impossible is nothing

Senior Manager
Joined: 01 Oct 2006
Posts: 498
Followers: 1

Kudos [?]: 20 [0], given: 0

Well missed that fist choice contains a Z...so anwer will be A.

Last edited by yogeshsheth on 29 Oct 2006, 21:59, edited 1 time in total.
Manager
Joined: 28 Oct 2006
Posts: 82
Followers: 1

Kudos [?]: 0 [0], given: 0

Hermione wrote:
I think III is also not defined. If z=-1, denominator becomes 0.

so maybe the answer is a. none

sorry, i don't have the oa for this. another kaplan question here.

ur right... none!
VP
Joined: 25 Jun 2006
Posts: 1173
Followers: 2

Kudos [?]: 79 [0], given: 0

none.

basically it means the denominator can't be 0 and find z.
Manager
Joined: 29 Aug 2006
Posts: 157
Followers: 1

Kudos [?]: 4 [0], given: 0

Re: PS: Unclear Question [#permalink]  29 Oct 2006, 20:09
Hermione wrote:
Which of the following expressions is defined for all integer values of z, such that z^2<9?

I. (z+1)/ z

II. (z-4)/ z^2-4z+4

III. 18/ z^2 -4z-5

a. none
b. I only
c. II only
d. III only
e. II and III only

... I'm not sure what the question is asking for... This is from Kaplan.

The question asks which of the options gives a defined answer for z^2<9
If z^2<9, then -3<z<3, i.e z can be -2,-1,0, 1 and 2

For each of the options, if the denominator=0, then the term is not defined.
For z+1/z, denom z cannot be 0, which is one of the values for z
For (z-4)/ z^2-4z+4, denom z^2-4z+4 cannot be zero, which means z cant be 2, which is one of the values for z
Finally, for 18/ z^2 -4z-5, z^2 -4z-5 cannot be zero which means z cant be 5 or -1. Since -1 is one of the possible values for z, this term also cannot be defined by z.

Re: PS: Unclear Question   [#permalink] 29 Oct 2006, 20:09
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