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Which of the following inequalities has a solution set that,

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Intern
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Which of the following inequalities has a solution set that, [#permalink] New post 21 Oct 2007, 08:02
Which of the following inequalities has a solution set that, when graphed on the number line, is a single line segment of finite length?

a. x^4 >= 1
b. x^3 <27>= 16
d. 2 <= |x| <= 5
e. 2 <= 3x + 4 <= 6
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 [#permalink] New post 21 Oct 2007, 08:12
(E) for me :)

2 <= 3x + 4 <= 6
<=> -2 <= 3*x <= 2
<=> -2/3 <= x <= 2/3

Last edited by Fig on 21 Oct 2007, 08:34, edited 2 times in total.
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 [#permalink] New post 21 Oct 2007, 08:22
can you explain it to me on how to approach this problem?

Thanks!
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 [#permalink] New post 21 Oct 2007, 08:30
Yes, I can try :)

I have activated the "Disable HTML in this post" option on your first post.... Please repost the question in it :)

The question is basically asking u if x is limited and so not running to infinite....

Normally, a glance on each answer makes it... but, to be sure on some answers, we could transform the inequalities to obtain x alone :)

More once u update :)
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 [#permalink] New post 05 Dec 2007, 05:13
Fig:

Can you explain why not B? I thing B and E both are finite and continuous.
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 [#permalink] New post 05 Dec 2007, 23:35
Fig wrote:
Yes, I can try :)

I have activated the "Disable HTML in this post" option on your first post.... Please repost the question in it :)

The question is basically asking u if x is limited and so not running to infinite....

Normally, a glance on each answer makes it... but, to be sure on some answers, we could transform the inequalities to obtain x alone :)

More once u update :)


Ya but be careful with just glancing. I almost picked A b/c I was too lazy to write this down on paper.

Only E works or so I think. I can't quite make out what B is suppose to be.

Still im pretty sure its E.
  [#permalink] 05 Dec 2007, 23:35
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