dr_sabr wrote:

D looks tempting but I will choose E.

-2<x<4

Add 2 to each side of the inequality

0<x+2<6

Therefore non of the available answers will fit with this inequality.

Correct me if I am mistaken.

adding numbers doesn't change the inequality. the inequality remains the same. you said that x+2<6 ==> x<4 ----so we're back to square one.

you have to do it this way.

To check for B.

if x>1 , |x-1| = x-1 then inequality is x-1<3 or x<4

x>1 and x<4 are consistent

if x<1, |x-1| = -(x-1) then inequality is -(x-1)<3 or x>-2

x>-2 and x<1 is again consistent.

Therefore B is correct.

If you try with other answers, you will land up with inconsistent inequalities.

I don't know if there is a shorter method.

Does anyone know a shorter(and quicker) method ?

- ash

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ash

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I'm crossing the bridge.........