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# Which of the following inequalitieshas a solution set that

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Which of the following inequalitieshas a solution set that [#permalink]

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05 Oct 2008, 06:47
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Which of the following inequalitieshas a solution set that when graphed on the number line, is a single line segment of finite length.

a) x^4 > or = 1
b) X^3 < or = 27
c) x^2 > or = 16
d) 2 < or = |x|< or = 5
e) 2 < or = 3x + 4 < or = 6
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Re: which of the following [#permalink]

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05 Oct 2008, 11:50
E. When you simplify, this reduces to -2/3 <= x <= 2/3.
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Re: which of the following [#permalink]

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06 Oct 2008, 14:23
Vavali wrote:
Which of the following inequalitieshas a solution set that when graphed on the number line, is a single line segment of finite length.

a) x^4 > or = 1
b) X^3 < or = 27
c) x^2 > or = 16
d) 2 < or = |x|< or = 5
e) 2 < or = 3x + 4 < or = 6

itis obvious taht ABC are infinite and D and E are finite. But whats the diff. bet D and E? how do we say E is finite and D is not? for me D and E, both, look finite.

D. 2 < or = |x|< or = 5
-5 < x < 5
so iti s finite.

E. 2 <= 3x + 4 <= 6
(2-4) <= 3x <= (6-4)
-2 <= 3x <= 2
-2/3 <= x <= 2/3

also finite

is this question complete?
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Re: which of the following [#permalink]

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07 Oct 2008, 02:49
GMAT TIGER wrote:
Vavali wrote:
Which of the following inequalitieshas a solution set that when graphed on the number line, is a single line segment of finite length.

a) x^4 > or = 1
b) X^3 < or = 27
c) x^2 > or = 16
d) 2 < or = |x|< or = 5
e) 2 < or = 3x + 4 < or = 6

itis obvious taht ABC are infinite and D and E are finite. But whats the diff. bet D and E? how do we say E is finite and D is not? for me D and E, both, look finite.

D. 2 < or = |x|< or = 5
-5 < x < 5
so iti s finite.

E. 2 <= 3x + 4 <= 6
(2-4) <= 3x <= (6-4)
-2 <= 3x <= 2
-2/3 <= x <= 2/3

also finite

is this question complete?

Trying to understand why the question is not complete.
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Re: which of the following [#permalink]

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07 Oct 2008, 02:56
Quote:
d) 2 < or = |x|< or

Trying to understand why the question is not complete.

pls, can you explain the question itself
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Re: which of the following [#permalink]

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08 Oct 2008, 08:15
Vavali wrote:
Which of the following inequalitieshas a solution set that when graphed on the number line, is a single line segment of finite length.

a) x^4 > or = 1
b) X^3 < or = 27
c) x^2 > or = 16
d) 2 < or = |x|< or = 5
e) 2 < or = 3x + 4 < or = 6

a) infinite
b) infinite
c) infinite
d) finite but two segments: x between -5 and -2 and x between 2 and 5.
e) one finite segment

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Re: which of the following [#permalink]

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10 Oct 2008, 05:18
Explanation of the question:

Vavali wrote:
Which of the following inequalities has a solution set that when graphed on the number line, is a single line segment of finite length.

There are several inequailities below. Their solutions can be presented as a set of line segments, some of which might be finite and some infinite. Which one of the equations has a solution set that consists of only one finite length segment.

Vavali wrote:
a) x^4 > or = 1

solution is a set of two intervals of infinte length x<-1 and x>1

Vavali wrote:
b) X^3 < or = 27

solution is a set of one interval of inifite length x<3
Vavali wrote:
c) x^2 > or = 16

solution is a set of two intervals of infinite length x<-4 and x>4
Vavali wrote:
d) 2 < or = |x|< or = 5

solution is a sete of two intervals of finite length -5<x<-2 and 2<x<5
Vavali wrote:
e) 2 < or = 3x + 4 < or = 6

solution is a set of one interval of finite length -2/3<x<2/3

I hope that helps!
Re: which of the following   [#permalink] 10 Oct 2008, 05:18
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