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Then start from the lowest one (E) it can not be devided by 9 - out
Then (D) can not be devided by 4 - out
Now (C) can be devided by any of these integers.
Integer is devided by 2 if it's even.
..... by 3 and 9 if sum of all digits is devided by 3.
..... by 4 if the last two digits are devided by 4.
..... by 6 if the integer is devided by 2 and by 3.
..... by 5 if the integer ends on zero or 5.
Your procedure would work fine as long as the answers dont have multiples of the LCM. Say if C = 5040 which is 2520*2 then ..
So taking the LCM is the best approach.
"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."
- Bernard Edmonds
Last edited by giddi77 on 05 Jul 2006, 06:30, edited 1 time in total.