|
Author |
Message |
|
TAGS:
|
|
|
Intern
Joined: 08 Jan 2007
Posts: 42
Followers: 1
Kudos [?]:
0
[0], given: 0
|
Which of the following is the lowest positive integer that [#permalink]
13 Feb 2007, 11:10
Which of the following is the lowest positive integer that is divisible by 2, 3, 4, 5, 6, 7, 8 and 9?
A)15120
B)3024
C)2520
D)1890
E)1080
Please provide explanation.
|
|
|
|
|
|
|
Manager
Joined: 12 Feb 2007
Posts: 168
Followers: 1
Kudos [?]:
0
[0], given: 0
|
As goofy as the page looks, it probably best to take a gander at these rules
I cant post the link for some dumb reason but take a look here
kidzworldDOTcomSLASHarticleSLASH4979-math-help-division-tips-and-tricks
Last edited by Tuneman on 13 Feb 2007, 11:57, edited 2 times in total.
|
|
|
|
|
|
Senior Manager
Joined: 23 Jun 2006
Posts: 398
Followers: 1
Kudos [?]:
293
[0], given: 0
|
1080 is not divisible by 7....
1890 not divisible by 8
C is the answer...
|
|
|
|
|
|
Senior Manager
Joined: 04 Jan 2006
Posts: 282
Followers: 1
Kudos [?]:
14
[0], given: 0
|
Find Least Common Factor of the given number.
LCM(2, 3, 4, 5, 6, 7, 8, 9) = 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2520
|
|
|
|
|
|
SVP
Joined: 05 Jul 2006
Posts: 1568
Followers: 4
Kudos [?]:
63
[0], given: 36
|
Re: Lowest Possible Integer [#permalink]
13 Feb 2007, 12:30
[quote="cucrose"]Which of the following is the lowest positive integer that is divisible by 2, 3, 4, 5, 6, 7, 8 and 9?
A)15120
B)3024
C)2520
D)1890
E)1080
1) b is not devisable by 5 ..............out ( it has to end up in 5 or 0)
2)d is not devisble by 4..........out ( check last 2 digits of any number /4)
3) e and is not devisable by 7 ......out
those u can spot at no time during the test
now we end up with c and a
C IS THE ANSWER(question ask for lowest)
|
|
|
|
|
|
Intern
Joined: 08 Jan 2007
Posts: 42
Followers: 1
Kudos [?]:
0
[0], given: 0
|
Devilmirror, can you please explain how you obtained these values? Thanks a lot.
devilmirror wrote: Find Least Common Factor of the given number.
LCM(2, 3, 4, 5, 6, 7, 8, 9) = 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2520
|
|
|
|
|
|
Senior Manager
Joined: 04 Jan 2006
Posts: 282
Followers: 1
Kudos [?]:
14
[0], given: 0
|
cucrose wrote: Devilmirror, can you please explain how you obtained these values? Thanks a lot. devilmirror wrote: Find Least Common Factor of the given number.
LCM(2, 3, 4, 5, 6, 7, 8, 9) = 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2520
LCM(2, 3, 4, 5, 6, 7, 8, 9) = 2 x 2 x 2 x 3 x 3 x 5 x 7 = 2520
This is the most straight forward method to find LCM.
2 = 2
4 = 2 x 2
5 = _________________x 5
6 = 2 x ______x 3
7 = _____________________x 7
8 = 2 x 2 x 2
9 = __________3 x 3
You reduce each repeated commond factor to be 1 number.
LCM = 2 x 2 x 2 x 3 x 3 x 5 x 7
|
|
|
|
|
|
Intern
Joined: 08 Jan 2007
Posts: 42
Followers: 1
Kudos [?]:
0
[0], given: 0
|
now it makes sense, thank you
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|