Which of the following lists the number of points at which a : Quant Question Archive [LOCKED]
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# Which of the following lists the number of points at which a

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Which of the following lists the number of points at which a [#permalink]

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01 Apr 2006, 15:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Which of the following lists the number of points at which a circle can intersect a triangle??
1. 2 and 6
2. 2, 4 and 6
3. 1,2,3 and 6
4. 1,2,3,4, and 6
5. 1,2,3,4,5 and 6

I got the answer right.. just was not sure, if I did it the right way..the question does not make sense to me
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Director
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02 Apr 2006, 01:13
I got E.. too but can you guys please explain why you chose E?
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02 Apr 2006, 01:57
E is correct if the circle and triangle can be tangent to each other. Not sure if tangent = intersect
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02 Apr 2006, 02:28
Yep! It instersects at just 1 point!
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02 Apr 2006, 03:49
GMATT73 wrote:
E is correct if the circle and triangle can be tangent to each other. Not sure if tangent = intersect

I totally agree. Strictly speaking, that's a difference. Then
the answer would be 2, 4, 6 --> B.
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04 Apr 2006, 14:43
I will go for B as I think a tangent never intersects a circle only a chord does...
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04 Apr 2006, 15:47
The Tangent Intersects the circle at 1 point!

"In plane geometry, a straight line is tangent to a curve, at some point, if both line and curve pass through the point with the same direction; "

Thats the definition of Tangent!
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04 Apr 2006, 15:51
If I understand the question correctly, it should be E, six points. If you look at the attached figure, you can see that it can (at most) intersect at six points.
Attachments

Circle.JPG [ 4.79 KiB | Viewed 713 times ]

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04 Apr 2006, 19:32
max possibility 6 points. Ans is E
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05 Apr 2006, 03:36
sm176811 wrote:
The Tangent Intersects the circle at 1 point!

"In plane geometry, a straight line is tangent to a curve, at some point, if both line and curve pass through the point with the same direction; "

Thats the definition of Tangent!

Thanks sm176811......I concur with you idea now
05 Apr 2006, 03:36
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