Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
which of the following must be true? (no restrictions of [#permalink]
29 May 2007, 17:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
which of the following must be true?
(no restrictions of signs of x or y)
I. 0 > -(x+y)^2
II.0 > -(x-y)^2
2. I only
3. II only
4. I and II
5. Cannot be determined
If you can, please provide an ALGEBRAIC SOLUTION/DERIVATION/PROOF for the two inequations. I got some answers after testing with several numbers - but it took a while and number plug-in method makes me unsure. Thanks.
i don't know if I am correct here, where did this Q come from? my order of operations may have been screwed up
my first answer was 4:
my reason: any number squared is positive. the values of x and y are irrelevant to the question. any combination of x and y will either be 1: positive or 2: negative. whatever the value, when it is squared it will be >0. then any positve number multiplied by negative 1 is negative.
then when i thought about it, we don't know if x and y are different numbers. if x and y are the same then 0^2 = 0. so II was out. also, because we don't know the values of x and y, y could =-x then we would have another situation where we are squaring zero. so my final answer is 5 - can not be determined.
please comment on my reasoning... i have been trying to practice with these sorts of problems as they are one of my weaknesses
1. None 2. I only 3. II only 4. I and II 5. Cannot be determined
Won't the answer be 1? the right side of the equation is squared and will always be positive (integer, non-integer) unless the right side equals 0. Both instances would result in the above being false.
also, someone mentioned order of operations. won't we distribute the negative signs in both equations before squaring them?