Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

which of the following must be true? (no restrictions of [#permalink]
29 May 2007, 16:07

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

which of the following must be true?
(no restrictions of signs of x or y)

I. 0 > -(x+y)^2
II.0 > -(x-y)^2

1. None
2. I only
3. II only
4. I and II
5. Cannot be determined

If you can, please provide an ALGEBRAIC SOLUTION/DERIVATION/PROOF for the two inequations. I got some answers after testing with several numbers - but it took a while and number plug-in method makes me unsure. Thanks.

i don't know if I am correct here, where did this Q come from? my order of operations may have been screwed up

my first answer was 4:

my reason: any number squared is positive. the values of x and y are irrelevant to the question. any combination of x and y will either be 1: positive or 2: negative. whatever the value, when it is squared it will be >0. then any positve number multiplied by negative 1 is negative.

then when i thought about it, we don't know if x and y are different numbers. if x and y are the same then 0^2 = 0. so II was out. also, because we don't know the values of x and y, y could =-x then we would have another situation where we are squaring zero. so my final answer is 5 - can not be determined.

please comment on my reasoning... i have been trying to practice with these sorts of problems as they are one of my weaknesses

1. None 2. I only 3. II only 4. I and II 5. Cannot be determined

Won't the answer be 1? the right side of the equation is squared and will always be positive (integer, non-integer) unless the right side equals 0. Both instances would result in the above being false.

also, someone mentioned order of operations. won't we distribute the negative signs in both equations before squaring them?

the order of ops says we should first take care of exponents, and then multiplication. a negative outside parentheses is the same thing as multiplying by -1.

ethan,

i guess the answer is 1 instead of 5; nice catch there. its not that it can't be determined... duh... we determined that the statements aren't true.

the order of ops says we should first take care of exponents, and then multiplication. a negative outside parentheses is the same thing as multiplying by -1.

ethan,

i guess the answer is 1 instead of 5; nice catch there. its not that it can't be determined... duh... we determined that the statements aren't true.

the order of ops says we should first take care of exponents, and then multiplication. a negative outside parentheses is the same thing as multiplying by -1.

sorry, you're correct. numbers b/w parens is first ... not numbers outside of parens.