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Which of the following represents the complete range of x [#permalink]
 08 Feb 2011, 09:29
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Which of the following represents the complete range of x over which x^3 – 4x^5 < 0? A. 0 < |x| < ½ B. |x| > ½ C. –½ < x < 0 or ½ < x D. x < –½ or 0 < x < ½ E. x < –½ or x > 0
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Re: Everything is Less Than Zero [#permalink]
08 Feb 2011, 09:41
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Re: Everything is Less Than Zero [#permalink]
09 Feb 2011, 23:41
Thanks Bunuel. +1 A question - what is the best way u use to know if the "good" area is above or below? i mean - what was the best way for u to know that its between -1/2 to 0 i used numbers ex. 1/4 but it consumes time! is there any better technique? thanks.
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Re: Everything is Less Than Zero [#permalink]
10 Feb 2011, 03:28
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144144 wrote: Thanks Bunuel. +1
A question - what is the best way u use to know if the "good" area is above or below?
i mean - what was the best way for u to know that its between -1/2 to 0
i used numbers ex. 1/4 but it consumes time! is there any better technique?
thanks. Check the link in my previous post. There are beautiful explanations by gurpreetsingh and Karishma. General idea is as follows: We have: (1+2x)*x^3*(1-2x)<0 --> roots are -1/2, 0, and 1/2 (equate the expressions to zero to get the roots and list them in ascending order), this gives us 4 ranges: x<-\frac{1}{2}, -\frac{1}{2}<x<0, 0<x<\frac{1}{2} and x>\frac{1}{2} --> now, test some extreme value: for example if x is very large number than first two terms ((1+2x) and x) will be positive but the third term will be negative which gives the negative product, so when x>\frac{1}{2} the expression is negative. Now the trick: as in the 4th range expression is negative then in 3rd it'll be positive, in 2nd it'l be negative again and finally in 1st it'll be positive: + - + -. So, the ranges when the expression is negative are: -\frac{1}{2}<x<0 (2nd range) or x>\frac{1}{2} (4th range). Hope its clear.
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Re: Everything is Less Than Zero [#permalink]
13 Feb 2011, 21:31
Hi Bunuel I'm getting D as answer : x^3(1-2x)(1+2x) < 0 -ve --- -1/2---- +ve--- 0----- -ve-----1/2--- +veCould you please explain where I'm wrong ? Regards, Subhash
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Re: Everything is Less Than Zero [#permalink]
13 Feb 2011, 22:05
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subhashghosh wrote: Hi Bunuel
I'm getting D as answer :
x^3(1-2x)(1+2x) < 0
-ve --- -1/2---- +ve--- 0----- -ve-----1/2--- +ve
Could you please explain where I'm wrong ?
Regards,
Subhash Even though your question is directed to Bunuel, I will give a quick explanation. The concept of the rightmost section being positive is applicable when every term is positive in the rightmost region. This is the case whenever the expressions involved are of the form (x - a) or (ax - b) etc. When you have a term such as (1-2x), the rightmost region becomes negative. So either, as Bunuel mentioned, check for an extreme value of x or convert (1-2x) to (2x - 1) and flip the sign to >.
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Re: Everything is Less Than Zero [#permalink]
15 Feb 2011, 14:33
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Re: Everything is Less Than Zero [#permalink]
02 Mar 2011, 18:04
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Re: Everything is Less Than Zero [#permalink]
02 Mar 2011, 18:40
Karishma I flipped the sign before. So I got x^3(2x-1)(2x-1) > 0 2 cases - both +ve or both -ve case 1 ------- x > 0 and |x| > 1/2. Hence x > 1/2 case 2 ------ x < 0 and 4x^2 - 1 < 0 x < 0 and -1/2 < x < 1/2 Taking the most restrictive value- -1/2 < x < 0 I hope this is correct. Btw this is 750 level in 2 mins. VeritasPrepKarishma wrote: subhashghosh wrote: Hi Bunuel
I'm getting D as answer :
x^3(1-2x)(1+2x) < 0
-ve --- -1/2---- +ve--- 0----- -ve-----1/2--- +ve
Could you please explain where I'm wrong ?
Regards,
Subhash Even though your question is directed to Bunuel, I will give a quick explanation. The concept of the rightmost section being positive is applicable when every term is positive in the rightmost region. This is the case whenever the expressions involved are of the form (x - a) or (ax - b) etc. When you have a term such as (1-2x), the rightmost region becomes negative. So either, as Bunuel mentioned, check for an extreme value of x or convert (1-2x) to (2x - 1) and flip the sign to >. |
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Re: Everything is Less Than Zero [#permalink]
02 Mar 2011, 19:12
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gmat1220 wrote: Karishma
I flipped the sign before. So I got x^3(2x-1)(2x-1) > 0
2 cases - both +ve or both -ve
case 1
-------
x > 0 and |x| > 1/2. Hence x > 1/2
case 2
------
x < 0 and 4x^2 - 1 < 0
x < 0 and -1/2 < x < 1/2
Taking the most restrictive value-
-1/2 < x < 0
I hope this is correct. Btw this is 750 level in 2 mins.
Yes, it is correct... and since you know what you are doing, you will need to work very hard to fall short of time on GMAT.
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Re: Everything is Less Than Zero [#permalink]
04 Mar 2011, 02:52
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Which of the following represents the complete range of x ov [#permalink]
02 Mar 2012, 11:45
Which of the following represents the complete range of x over which x^3 – 4x^5 < 0? (A) 0 < |x| < ½ (B) |x| > ½ (C) –½ < x < 0 or ½ < x (D) x < –½ or 0 < x < ½ (E) x < –½ or x > 0
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Re: Which of the following represents the complete range of x ov [#permalink]
02 Mar 2012, 11:53
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Re: Everything is Less Than Zero [#permalink]
11 Jun 2012, 05:42
VeritasPrepKarishma wrote: gmat1220 wrote: Karishma
I flipped the sign before. So I got x^3(2x-1)(2x-1) > 0
2 cases - both +ve or both -ve
case 1
-------
x > 0 and |x| > 1/2. Hence x > 1/2
case 2
------
x < 0 and 4x^2 - 1 < 0
x < 0 and -1/2 < x < 1/2
Taking the most restrictive value-
-1/2 < x < 0
I hope this is correct. Btw this is 750 level in 2 mins.
Yes, it is correct... and since you know what you are doing, you will need to work very hard to fall short of time on GMAT. Thanks for the explanation. It's very useful to know to solve any problem with different approaches...
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Re: Everything is Less Than Zero [#permalink]
20 Jun 2012, 22:42
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gmatpapa wrote: Which of the following represents the complete range of x over which x^3 - 4x^5 < 0?
(A) 0 < |x| < ½
(B) |x| > ½
(C) –½ < x < 0 or ½ < x
(D) x < –½ or 0 < x < ½
(E) x < –½ or x > 0 Responding to a pm: The problem is the same here. How do you solve this inequality: (1+2x)*x^3*(1-2x)<0Again, there are 2 ways - The long algebraic method: When is (1+2x)*x^3*(1-2x) negative? When only one of the terms is negative or all 3 are negative. There will be too many cases to consider so this is painful. The number line method: Multiply both sides of (1+2x)*x^3*(1-2x)<0 by -1 to get (2x + 1)*x^3*(2x - 1)>0Take out 2 common to get 2(x + 1/2)*x^3*2(x - 1/2)>0 [because you want each term to be of the form (x + a) or (x - a)] Now plot them on the number line and get the regions where this inequality holds. Basically, you need to go through this entire post: inequalities-trick-91482.html
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Re: Which of the following represents the complete range of x [#permalink]
21 Jun 2012, 19:11
thankyou, actually after your reply to the other thread this one i got very easily.
Also the lnk is best for summary as well that you posted.
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Re: Which of the following represents the complete range of x [#permalink]
01 Nov 2012, 16:06
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Bunuel
Thanx a trillion for your post on solving inequalities using graph
You know i paid over 300$ to test prep institutes but got nothing out of it.......when i asked such basic question the tutor got frustrated and insulted me.....But hats off to you... MAx wat will i give 1 kudo......
Wat an expeirence it has been with GMAt club
Thanx a lot Bunuel
Trillion kudos to you and Hats off to you for addressing problems with patience..............I cant express myself how satisfied i am feeling.
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Re: Which of the following represents the complete range of x [#permalink]
15 Nov 2012, 13:58
Hi All,
Could I conclude that for this case i.e (1+2x)*x^3*(1-2x)<0
even if one of the terms <0, that does not necessarily mean that the entire product of the 3 terms <0.
Cause like if the eq was (1+2x)*x^3*(1-2x)= 0 ....I could have safely concluded that
However in this case for the entire product <0.. either 1 terms or 2 terms or even all 3 terms can be - ve.
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Re: Which of the following represents the complete range of x [#permalink]
15 Nov 2012, 19:03
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lesnin wrote: Hi All,
Could I conclude that for this case i.e (1+2x)*x^3*(1-2x)<0
even if one of the terms <0, that does not necessarily mean that the entire product of the 3 terms <0.
Cause like if the eq was (1+2x)*x^3*(1-2x)= 0 ....I could have safely concluded that
However in this case for the entire product <0.. either 1 terms or 2 terms or even all 3 terms can be - ve. When you have product of two or more terms, the product will be negative only when odd number of terms are negative i.e. either only one term is negative and rest are positive or only 3 terms are negative and rest are positive or only 5 terms are negative and rest are positive. (-)(+)(+) = (-) (-)(-)(+) = (+) (-)(-)(-) = (-)
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Re: Which of the following represents the complete range of x [#permalink]
06 Dec 2012, 04:15
Using the amazing technique:
x^3(1-4x^2)<0
x^3(1-2x)(1+2x)<0
+ (-1/2) - (0) + (1/2) -
If less than 0, select (-) curves.
Answer: -1/2 < x < 0 or 1/2 < x ==> C
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Re: Which of the following represents the complete range of x
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06 Dec 2012, 04:15
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