Bunuel wrote:

(x —1)(x + 3) > 0

(x +5)(x—4) < 0

Which of the following values of x satisfy both inequalities shown?

I. -6

II. -4

III. 2

IV. 5A. I and II only

B. I and III only

C. II and III only

D. II and IV only

E. I, II, III, and IV

(x - 1)(x + 3) > 0 --> x<-3 or x>1.

(x + 5)(x - 4) < 0 --> -5<x<4.

Among choices only -4 and 2 satisfy both inequalities.

Answer: C.

Solving inequalities:

x2-4x-94661.html#p731476inequalities-trick-91482.htmleverything-is-less-than-zero-108884.htmlxy-plane-71492.html Hi Bunuel,

What is the underlying concept to solve these types of inequalities ? When (x - 1)(x + 3) > 0 , we can assume that either both entities are negative or positive. You seem to have assumed both x-1 and x +3 to be positive. Please do let me know where I'm going wrong in in analysing your solution.

Thanks