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While on a straight road, Car X and Car Y are traveling at

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While on a straight road, Car X and Car Y are traveling at [#permalink] New post 17 Mar 2012, 18:44
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73% (01:45) correct 26% (01:11) wrong based on 10 sessions
While on a straight road, Car X and Car Y are traveling at different constant rates. If Car X is now 1 mile ahead of Car Y, how many minutes from now will Car X be 2 miles ahead of Car Y ?

(1) Car X is traveling at 50 miles per hour and Car Y is traveling at 40 miles per hour.
(2) Three minutes ago Car X was 1/2 mile ahead of Car Y.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 07 Dec 2012, 10:38, edited 1 time in total.
Renamed the topic and edited the question.
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Re: GMAT Paper Tests 1 [#permalink] New post 17 Mar 2012, 21:22
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A follows B, Time to catchup = (Distance between A and B)/(SA - SB)

A)
SA - SB is the relative speed = 50-40=10 m/hr
Distance between A and B = 2-1 = 1.

Therefore, Time to catchup = 1/10 hours = 0.1*60 minutes = 6 mintues

Sufficient.

B)
3 minutes for 1/2 mile
Therefore 1 mile will be 6 minutes

Sufficient

Thus D.
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Re: While on a straight road, car X and car Y are traveling at [#permalink] New post 18 Mar 2012, 07:21
While on a straight road, Car X and Car Y are traveling at different constant rates. If Car X is now 1 mile ahead of Car Y, how many minutes from now will Car X be 2 miles ahead of Car Y ?

(1) Car X is traveling at 50 miles per hour and Car Y is traveling at 40 miles per hour --> since we have the rates of both cars and the distance between them we can calculate any other question regarding them. Sufficient.

(2) Three minutes ago Car X was 1/2 mile ahead of Car Y --> car X gains 1/2 mile in every 3 minutes (since now it's 1 mile ahead), hence it'll gain additional 1 mile in next 6 minutes. Sufficient.

Answer: D.
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Re: While on a straight road, car X and car Y are traveling at [#permalink] New post 11 Nov 2012, 01:54
Bro Bunuel,

How to solve this to get the time in secs if we consider this as 2 independent PS questions?

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Re: While on a straight road, car X and car Y are traveling at [#permalink] New post 11 Nov 2012, 02:06
ok.. i just figured out..

1)

relative speed: 10 miles/ hour = 1/6 miles / min
distance to be covered: 1 mile.

time taken : 1/(1/6) = 6 mins..

2)
find the rate :
distance : 1/2 mile
time taken: 3 mins

rate: 1/6 miles / min

now,
distance=1 mile
rate : 1/6 miles/ min

so time: 6 mins

:lol:

hope it helps! ( Bunuel's statement :) )
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Re: While on a straight road, car X and car Y are traveling at   [#permalink] 11 Nov 2012, 02:06
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