With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. What is the capacity of the pool if every minute the second valve admits 50 cubic meters of water more than the first?

* 9000 cubic meters

* 10500 cubic meters

* 11750 cubic meters

* 12000 cubic meters

* 12500 cubic meters

With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. What is the capacity of the pool if every minute the second valve admits 50 cubic meters of water more than the first?

Soln:

Let volume filled by first valve per minute = Va cubic meter

As first valve takes 2hours to fill the pool

therefore volume of the pool = 120 x Va....(1)

Let the volume filled by second valve per minute = Vb cubic meter

Total volume filled by both the valves in 48 minutes = Va x 48 + Vb x 48

According to the condition of the problem

Vb = Va + 50

therefore total vulme filled in 48 minutes

Va x 48 + (Va+50) x 48 = volume of the pool = 120 Va ..from (1)

or, Va = 100

Total volume of the pool = 100 x 120 = 12000 cubic meters

Option D

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