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19 Dec 2012, 04:01
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100% (02:52) correct 0% (00:00) wrong based on 12 sessions

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Wonka Bars sell for $1 each. Willy Wonka also accepts three Wonka Bar wrappers in exchange for a Wonka Bar. Violet has$8 and Veruca has $7. If they decide to pool their money together, buy the maximum possible number of Wonka bars and split the bars equally between them, how many Wonka bars will Veruca have? A) 10 B) 11 C) 15 D) 20 E) 22 Not my own question per se. A common math problem just tweaked a bit to make a PS question... Please feel free to provide your feedback... No OA.. Answer is my own.. [Reveal] Spoiler: My answer is B _________________ Did you find this post helpful?... Please let me know through the Kudos button. Thanks To The Almighty - My GMAT Debrief GMAT Reading Comprehension: 7 Most Common Passage Types VP Status: Been a long time guys... Joined: 03 Feb 2011 Posts: 1420 Location: United States (NY) Concentration: Finance, Marketing GPA: 3.75 Followers: 170 Kudos [?]: 1169 [0], given: 62 Re: Wonka Bars sell for$1 each. [#permalink]

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19 Dec 2012, 11:03
They together have $15 with which they can buy 15 bars. These 15 bars will generate 15 wrappers. Now we will utilise the given fact i.e. 3 wrappers can buy 1 bar. Hence with the 15 wrappers, we can buy 5 bars. With these 5 bars, # of wrappers generated are 5, of which 3 are utilised to get another bar and 2 are left. The last bar will further give a wrapper that when combined with the leftover 2 wrappers will yield us another bar. All in all 22 bars. So each one will get 11 bar. _________________ Re: Wonka Bars sell for$1 each.   [#permalink] 19 Dec 2012, 11:03
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