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hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

Re: WORDS PROBLEMS [#permalink]
02 Jun 2005, 01:15

mandy wrote:

hello canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is (A) 1987 (B) 1988 (C) 1991 (D) 1992

Re: WORDS PROBLEMS [#permalink]
02 Jun 2005, 07:05

mandy wrote:

hello canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is (A) 1987 (B) 1988 (C) 1991 (D) 1992 (E) 2000

I vote for D.

John earns 5000 less than Don, and he makes closes the gap by 450 a year.
So he would take 5000/450 = [100/9] years to close this gap , where [] = next highest integer.

Re: WORDS PROBLEMS [#permalink]
03 Jun 2005, 09:56

mandy wrote:

hello canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is (A) 1987 (B) 1988 (C) 1991 (D) 1992 (E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when
15000 + 2450x > 20000 + 2000x
450x > 5000
x > 11.1

thus the first year will be after 12 years, i.e. 1992

Re: WORDS PROBLEMS [#permalink]
21 May 2007, 22:46

cloudz9 wrote:

mandy wrote:

hello canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is (A) 1987 (B) 1988 (C) 1991 (D) 1992 (E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when 15000 + 2450x > 20000 + 2000x 450x > 5000 x > 11.1

thus the first year will be after 12 years, i.e. 1992

thanks. simple yet couldnt think of it at the moment,

For this kind of a problem, my tendency is to write an algebraic equation, but its better to solve this with the logic HTMG used, making up the deficit of $5000 in $450 installments/year....and computing how long it'll take to do this.

Re: WORDS PROBLEMS [#permalink]
22 May 2007, 21:30

bmwhype2 wrote:

cloudz9 wrote:

mandy wrote:

hello canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was $20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of $2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is (A) 1987 (B) 1988 (C) 1991 (D) 1992 (E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when 15000 + 2450x > 20000 + 2000x 450x > 5000 x > 11.1

thus the first year will be after 12 years, i.e. 1992

thanks. simple yet couldnt think of it at the moment,

it should be simple.

15,000 + n (2,450) = 20,000 + n (2,000)
n = 11.xxxx

since now it is 1980, it is 1992 (12 more years from now) to have John's salary to be greater than donna's.

gmatclubot

Re: WORDS PROBLEMS
[#permalink]
22 May 2007, 21:30