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# WORDS PROBLEMS

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Senior Manager
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02 Jun 2005, 02:00
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hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000
Director
Joined: 18 Apr 2005
Posts: 548
Location: Canuckland
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02 Jun 2005, 02:15
mandy wrote:
hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992

(E) 2000

15,000 + (x-1980 -1)*2,450 = 20,000 + (x-1980 -1)*2,000

x is the year
Senior Manager
Joined: 19 Feb 2005
Posts: 486
Location: Milan Italy
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02 Jun 2005, 06:43
that makes 1992 the answer...I hope!
Senior Manager
Joined: 17 Apr 2005
Posts: 375
Location: India
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02 Jun 2005, 08:05
mandy wrote:
hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

I vote for D.

John earns 5000 less than Don, and he makes closes the gap by 450 a year.
So he would take 5000/450 = [100/9] years to close this gap , where [] = next highest integer.

HMTG.
Senior Manager
Joined: 15 Apr 2005
Posts: 417
Location: India, Chennai
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02 Jun 2005, 21:38
My answer is 1992, and my approach to the problem was same as HMTG

Thanks
Senior Manager
Joined: 17 May 2005
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03 Jun 2005, 10:56
mandy wrote:
hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when
15000 + 2450x > 20000 + 2000x
450x > 5000
x > 11.1

thus the first year will be after 12 years, i.e. 1992
CEO
Joined: 21 Jan 2007
Posts: 2756
Location: New York City
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21 May 2007, 23:46
cloudz9 wrote:
mandy wrote:
hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when
15000 + 2450x > 20000 + 2000x
450x > 5000
x > 11.1

thus the first year will be after 12 years, i.e. 1992

thanks. simple yet couldnt think of it at the moment,
Manager
Joined: 18 Sep 2006
Posts: 58
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22 May 2007, 22:07
For this kind of a problem, my tendency is to write an algebraic equation, but its better to solve this with the logic HTMG used, making up the deficit of $5000 in$450 installments/year....and computing how long it'll take to do this.
Director
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Posts: 904
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22 May 2007, 22:30
bmwhype2 wrote:
cloudz9 wrote:
mandy wrote:
hello
canyone knows how to solve this one and the equations to put thanks

In 1980 Johnâ€™s salary was $15,000 a year and Donâ€™s salary was$20,000 a year. If every year thereafter. John receives a raise of $2,450 and Don receives a raise of$2,000, the first year in which Johnâ€™s salary will be more than Donâ€™s salary is
(A) 1987
(B) 1988
(C) 1991
(D) 1992
(E) 2000

if x is the number of years that John has to wait to get paid more than Don..we have to find x when
15000 + 2450x > 20000 + 2000x
450x > 5000
x > 11.1

thus the first year will be after 12 years, i.e. 1992

thanks. simple yet couldnt think of it at the moment,

it should be simple.

15,000 + n (2,450) = 20,000 + n (2,000)
n = 11.xxxx

since now it is 1980, it is 1992 (12 more years from now) to have John's salary to be greater than donna's.
Re: WORDS PROBLEMS   [#permalink] 22 May 2007, 22:30
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