Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: 'Work' Word Problems Made Easy [#permalink]
11 Aug 2013, 00:09

Hi,

Can sombody please solve this wit solution for this question.

It takes Printer A 4 more minutes than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. how long will it take printer A to print 80 pages? a. 12 b. 18 c. 20 d. 24 e. 30

Re: 'Work' Word Problems Made Easy [#permalink]
11 Aug 2013, 00:14

Expert's post

rrsnathan wrote:

Hi,

Can sombody please solve this wit solution for this question.

It takes Printer A 4 more minutes than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. how long will it take printer A to print 80 pages? a. 12 b. 18 c. 20 d. 24 e. 30

Re: 'Work' Word Problems Made Easy [#permalink]
02 Sep 2013, 12:18

Just 3 hours back, literally I was at zero confidence to start with work rate problems, but after going through your notes and solving 5 or 6 problems, I have solved 80 to 90% difficulty level problems like a pro, solutions are also matching closely to Bunuel's. Really work rate is not that as much tough as I was thinking before. Reciprocate the hours to find the rate of work per day or per minute that's it half battle won-> "master key to every work rate problem".

Thanks allot. _________________

Piyush K ----------------------- Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison Don't forget to press--> Kudos My Articles: 1. WOULD: when to use?| 2. All GMATPrep RCs (New) Tip: Before exam a week earlier don't forget to exhaust all gmatprep problems specially for "sentence correction".

Re: 'Work' Word Problems Made Easy [#permalink]
16 Sep 2013, 22:46

Bunuel wrote:

resh924 wrote:

Bunuel,

Can you help me with this question?

A group of 5 craftsmen, working together at the same rate, can finish a job in 3 hours. How long will it take a group of 4 apprentices working together to do the same job? (1) Each apprentice works at 2/3 the rate of a craftsman. (2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job.

Answer choice seems to be D.

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance in rate problems.

time*speed=distance <--> time*rate=job \ done.

So, if we say that the rate of a craftsmen is x job/hours and the rate of an apprentice is y job/hour then we'll have (5x)*3=job=(4y)*t --> (5x)*3=(4y)*t. Question: t=\frac{15x}{4y}=?

(1) Each apprentice works at 2/3 the rate of a craftsman --> y=\frac{2}{3}x --> \frac{x}{y}=\frac{3}{2} --> t=\frac{15x}{4y}=\frac{45}{8} hours. Sufficient.

(2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job --> as the 5 craftsmen need 3 hours to do the job then in 45/23 hours they'll complete (45/23)/3=15/23 rd of the job (15 parts out of 23) so the rest of the job, or 1-15/23=8/23 (8 parts out of 23) is done by the 4 apprentices in the same amount of time (45/23 hours): \frac{5x}{4y}=\frac{15}{8} --> \frac{x}{y}=\frac{3}{2}, the same info as above. Sufficient.

Answer: D.

Hi Bunuel,

For #2, I set-up my equation as:

1/3 + 1/A = 1/(45/23)

Since we already know the rate of the 5 craftsmen and the total hours needed for the 2 groups to finish the job. However, I arrived at a different answer for A (45/8). I can't seem to figure out where it went wrong, hope you can help.

Re: 'Work' Word Problems Made Easy [#permalink]
16 Sep 2013, 23:43

Expert's post

pauc wrote:

Bunuel wrote:

resh924 wrote:

Bunuel,

Can you help me with this question?

A group of 5 craftsmen, working together at the same rate, can finish a job in 3 hours. How long will it take a group of 4 apprentices working together to do the same job? (1) Each apprentice works at 2/3 the rate of a craftsman. (2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job.

Answer choice seems to be D.

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance in rate problems.

time*speed=distance <--> time*rate=job \ done.

So, if we say that the rate of a craftsmen is x job/hours and the rate of an apprentice is y job/hour then we'll have (5x)*3=job=(4y)*t --> (5x)*3=(4y)*t. Question: t=\frac{15x}{4y}=?

(1) Each apprentice works at 2/3 the rate of a craftsman --> y=\frac{2}{3}x --> \frac{x}{y}=\frac{3}{2} --> t=\frac{15x}{4y}=\frac{45}{8} hours. Sufficient.

(2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job --> as the 5 craftsmen need 3 hours to do the job then in 45/23 hours they'll complete (45/23)/3=15/23 rd of the job (15 parts out of 23) so the rest of the job, or 1-15/23=8/23 (8 parts out of 23) is done by the 4 apprentices in the same amount of time (45/23 hours): \frac{5x}{4y}=\frac{15}{8} --> \frac{x}{y}=\frac{3}{2}, the same info as above. Sufficient.

Answer: D.

Hi Bunuel,

For #2, I set-up my equation as:

1/3 + 1/A = 1/(45/23)

Since we already know the rate of the 5 craftsmen and the total hours needed for the 2 groups to finish the job. However, I arrived at a different answer for A (45/8). I can't seem to figure out where it went wrong, hope you can help.

Thanks.

You should get the same answer: 1/3 + 1/A = 1/(45/23) --> A=45/8. _________________

Re: 'Work' Word Problems Made Easy [#permalink]
17 Sep 2013, 02:31

Quote:

Hi Bunuel,

For #2, I set-up my equation as:

1/3 + 1/A = 1/(45/23)

Since we already know the rate of the 5 craftsmen and the total hours needed for the 2 groups to finish the job. However, I arrived at a different answer for A (45/8). I can't seem to figure out where it went wrong, hope you can help.

Thanks.

You should get the same answer: 1/3 + 1/A = 1/(45/23) --> A=45/8.[/quote]

Oops, you're right. I was obsessing over a different value (3/2 from Statement 2). Thank you.

Re: 'Work' Word Problems Made Easy [#permalink]
25 Jul 2014, 17:23

Bunuel wrote:

resh924 wrote:

Bunuel,

Can you help me with this question?

A group of 5 craftsmen, working together at the same rate, can finish a job in 3 hours. How long will it take a group of 4 apprentices working together to do the same job? (1) Each apprentice works at 2/3 the rate of a craftsman. (2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job.

Answer choice seems to be D.

Time, rate and job in work problems are in the same relationship as time, speed (rate) and distance in rate problems.

time*speed=distance <--> time*rate=job \ done.

So, if we say that the rate of a craftsmen is x job/hours andthe rate of an apprentice is y job/hour then we'll have (5x)*3=job=(4y)*t --> (5x)*3=(4y)*t. Question: t=\frac{15x}{4y}=?

(1) Each apprentice works at 2/3 the rate of a craftsman --> y=\frac{2}{3}x --> \frac{x}{y}=\frac{3}{2} --> t=\frac{15x}{4y}=\frac{45}{8} hours. Sufficient.

(2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job --> as the 5 craftsmen need 3 hours to do the job then in 45/23 hours they'll complete (45/23)/3=15/23 rd of the job (15 parts out of 23) so the rest of the job, or 1-15/23=8/23 (8 parts out of 23) is done by the 4 apprentices in the same amount of time (45/23 hours): \frac{5x}{4y}=\frac{15}{8} --> \frac{x}{y}=\frac{3}{2}, the same info as above. Sufficient.

I agree with the answer you got but not the logic you used to arrive at the answer. The reason that I disagree with your logic is based on my understanding that DS questions are precise in their statements and we are not supposed to assume anything outside of what is stated. Can you please care to comment on the following?

Nowhere in the question stem it is mentioned that 4 apprentices work at the same rate. So, I am not sure if the highlighted portion in your solution is valid.

Statement 1: We can deduce that 4 apprentices work at the same rate since it says "Each apprentice works at 2/3 the rate of a craftsman" For statement 2, we cannot assume that the 4 apprentices work at the same rate. However, since the question asks us to find time taken by group of 4 apprentices and not one apprentice, this statement alone can give us the answer and hence sufficient.

Is my understanding correct or am I reading too much into this?

Re: 'Work' Word Problems Made Easy [#permalink]
12 Oct 2014, 15:12

Example 3. Working together, printer A and printer B would finish a task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A?

Solution: This problem is interesting because it tests not only our knowledge of the concept of word problems, but also our ability to ‘translate English to Math’

‘Working together, printer A and printer B would finish a task in 24 minutes’ This tells us that A and B combined would work at the rate of \frac{1}{24} per minute.

‘Printer A alone would finish the task in 60 minutes’ This tells us that A works at a rate of \frac{1}{60} per minute.

At this point, it should strike you that with just this much information, it is possible to calculate the rate at which B works: Rate at which B works = \frac{1}{24}-\frac{1}{60}=\frac{1}{40}.

[i]‘B prints 5 pages a minute more than printer A’[/i] This means that the difference between the amount of work B and A complete in one minute corresponds to 5 pages. So, let us calculate that difference. It will be \frac{1}{40}-\frac{1}{60}=\frac{1}{120}

‘How many pages does the task contain?’ If \frac{1}{120} of the job consists of 5 pages, then the 1 job will consist of \frac{(5*1)}{\frac{1}{120}} = 600 pages.

Is there any other way to tackle this part. I am not able to understand it.

Re: 'Work' Word Problems Made Easy [#permalink]
12 Oct 2014, 23:04

Expert's post

earnit wrote:

Example 3. Working together, printer A and printer B would finish a task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A?

Solution: This problem is interesting because it tests not only our knowledge of the concept of word problems, but also our ability to ‘translate English to Math’

‘Working together, printer A and printer B would finish a task in 24 minutes’ This tells us that A and B combined would work at the rate of \frac{1}{24} per minute.

‘Printer A alone would finish the task in 60 minutes’ This tells us that A works at a rate of \frac{1}{60} per minute.

At this point, it should strike you that with just this much information, it is possible to calculate the rate at which B works: Rate at which B works = \frac{1}{24}-\frac{1}{60}=\frac{1}{40}.

[i]‘B prints 5 pages a minute more than printer A’[/i] This means that the difference between the amount of work B and A complete in one minute corresponds to 5 pages. So, let us calculate that difference. It will be \frac{1}{40}-\frac{1}{60}=\frac{1}{120}

‘How many pages does the task contain?’ If \frac{1}{120} of the job consists of 5 pages, then the 1 job will consist of \frac{(5*1)}{\frac{1}{120}} = 600 pages.

Is there any other way to tackle this part. I am not able to understand it.