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Working together, printer A and printer B would finish the [#permalink]
 01 Sep 2010, 11:12
Question Stats:
65% (03:07) correct
34% (03:02) wrong based on 6 sessions
Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ? A. 600 B. 800 C. 1000 D. 1200 E. 1500 I know this question is relatively symol if make an equation in one vaibale ...
I tried to do it by applying the fundamental of A = Jobs per min * time ( the way we typically solve the work problems ) and i was stuck
I did jobs per minute A , 1/60
combined rate = 1/24
so rate of b = 1/24 - 1/60 = 1/40
but could not arrive at the solution ... i tried to form the equation by assuming x as the total numbe of pages So x/60+ x+5/40 = cld nt take ot forward from here
kindly see where am I losing the track !
Last edited by Bunuel on 06 Sep 2012, 10:01, edited 2 times in total.
Edited the question.
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Re: solution required [#permalink]
01 Sep 2010, 12:56
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gauravnagpal wrote: .Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ?
a. 600
b. 800
c. 1000
d. 1200
e. 1500
answer: A
I know this question is relatively symol if make an equation in one vaibale ...
I tried to do it by applying the fundamental of A = Jobs per min * time ( the way we typically solve the work problems ) and i was stuck
I did jobs per minute A , 1/60
combined rate = 1/24
so rate of b = 1/24 - 1/60 = 1/40
but could not arrive at the solution ... i tried to form the equation by assuming x as the total numbe of pages So x/60+ x+5/40 = cld nt take ot forward from here
kindly see where am I losing the track ! Let the rate of printer A be a pages per minute, the rate of printer B be b pages per minute and whole task be x pages. time*rate=job \ done: Working together, printer A and printer B would finish the task in 24 minutes" --> 24(a+b)=x; Printer A alone would finish the task in 60 minutes --> 60a=x; Printer B prints 5 pages a minute more than printer A --> b=a+5. Solving for x --> x=600. Answer: A. Some work problems with solutions: time-n-work-problem-82718.html?hilit=reciprocal%20ratefacing-problem-with-this-question-91187.html?highlight=rate+reciprocalwhat-am-i-doing-wrong-to-bunuel-91124.html?highlight=rate+reciprocalgmat-prep-ps-93365.html?hilit=reciprocal%20ratequestions-from-gmat-prep-practice-exam-please-help-93632.html?hilit=reciprocal%20ratea-good-one-98479.html?hilit=rateHope it helps.
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Re: solution required [#permalink]
03 Sep 2010, 11:26
1
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B in a minute=x/40
A in a minute=x/60
then,
x/40-x/60=5
Solving x=600
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Re: solution required [#permalink]
06 Sep 2012, 08:09
Bunuel wrote: gauravnagpal wrote: .Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ?
a. 600
b. 800
c. 1000
d. 1200
e. 1500
answer: A
I know this question is relatively symol if make an equation in one vaibale ...
I tried to do it by applying the fundamental of A = Jobs per min * time ( the way we typically solve the work problems ) and i was stuck
I did jobs per minute A , 1/60
combined rate = 1/24
so rate of b = 1/24 - 1/60 = 1/40
but could not arrive at the solution ... i tried to form the equation by assuming x as the total numbe of pages So x/60+ x+5/40 = cld nt take ot forward from here
kindly see where am I losing the track ! Let the rate of printer A be a pages per minute, the rate of printer B be b pages per minute and whole task be x pages. time*rate=job \ done: Working together, printer A and printer B would finish the task in 24 minutes" --> 24(a+b)=x; Printer A alone would finish the task in 60 minutes --> 60a=x; Printer B prints 5 pages a minute more than printer A --> b=a+5. Solving for x --> x=600. Answer: A. Some work problems with solutions: time-n-work-problem-82718.html?hilit=reciprocal%20ratefacing-problem-with-this-question-91187.html?highlight=rate+reciprocalwhat-am-i-doing-wrong-to-bunuel-91124.html?highlight=rate+reciprocalgmat-prep-ps-93365.html?hilit=reciprocal%20ratequestions-from-gmat-prep-practice-exam-please-help-93632.html?hilit=reciprocal%20ratea-good-one-98479.html?hilit=rateHope it helps. Hi Bunnel, I have always one confusion in rate and work problems can you please clarify this?, When do we add rates i.e what you did above...... 24(a+b)=x; and when do we divide by rates i.e something . rate =(Job done/ time) Regards Srinath
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Re: solution required [#permalink]
06 Sep 2012, 10:39
kotela wrote: Bunuel wrote: gauravnagpal wrote: .Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ?
a. 600
b. 800
c. 1000
d. 1200
e. 1500
answer: A
I know this question is relatively symol if make an equation in one vaibale ...
I tried to do it by applying the fundamental of A = Jobs per min * time ( the way we typically solve the work problems ) and i was stuck
I did jobs per minute A , 1/60
combined rate = 1/24
so rate of b = 1/24 - 1/60 = 1/40
but could not arrive at the solution ... i tried to form the equation by assuming x as the total numbe of pages So x/60+ x+5/40 = cld nt take ot forward from here
kindly see where am I losing the track ! Let the rate of printer A be a pages per minute, the rate of printer B be b pages per minute and whole task be x pages. time*rate=job \ done: Working together, printer A and printer B would finish the task in 24 minutes" --> 24(a+b)=x; Printer A alone would finish the task in 60 minutes --> 60a=x; Printer B prints 5 pages a minute more than printer A --> b=a+5. Solving for x --> x=600. Answer: A. Some work problems with solutions: time-n-work-problem-82718.html?hilit=reciprocal%20ratefacing-problem-with-this-question-91187.html?highlight=rate+reciprocalwhat-am-i-doing-wrong-to-bunuel-91124.html?highlight=rate+reciprocalgmat-prep-ps-93365.html?hilit=reciprocal%20ratequestions-from-gmat-prep-practice-exam-please-help-93632.html?hilit=reciprocal%20ratea-good-one-98479.html?hilit=rateHope it helps. Hi Bunnel, I have always one confusion in rate and work problems can you please clarify this?, When do we add rates i.e what you did above...... 24(a+b)=x; and when do we divide by rates i.e something . rate =(Job done/ time) Regards Srinath You can denote rate directly by some variable ( a in the solution) or express rate as a reciprocal of time. For example, say printer A needs t minutes to print 1 page and printer B needs m minutes to print 1 page, then the rate of printer A would be job/time=1/t pages per minute and the rate of printer B would be 1/m pages per minute (rate is a reciprocal of time, so 1/t=a and 1/m=b). In this case the equation would be 24(1/t+1/m)=x. Hope it's clear.
_________________
PLEASE READ AND FOLLOW: 11 Rules for Posting!!!
RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!
What are GMAT Club Tests?
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Find out what's new at GMAT Club - latest features and updates
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Re: Working together, printer A and printer B would finish the [#permalink]
08 Sep 2012, 05:51
First thing i did was i found out time that is required to B to complete the task alone: 1/24-1/60=3/120=1/40. Then i looked at the information which states that the rate of B is 5+ page than that of A so, lets say x is the number of pages printed by A per minute, so the task consists of 60*x or 40*(x+5) pages. I can make an equation: 60x=40(x+5), 20x=200, x=10, total number of pages is 60*10=600 or 40*15=600 Answer is A. It is clear but it took me about 3 min to do it, does it because i am doing it slow or i am using longer route?
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Re: Working together, printer A and printer B would finish the [#permalink]
15 Nov 2012, 05:37
\frac{1}{A}=\frac{1}{60}
\frac{1}{B}+\frac{1}{A}=\frac{1}{24}
Get: \frac{1}{B}
\frac{1}{B}=\frac{1}{24}-\frac{1}{60}=\frac{1}{40}
Let p be the number of pages produced by A.
Let p+5 be the number of pages produced by B.
24(p + p+5) = 60(p)==> p=10pages
Answer: 60(p)=600pages
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Re: Working together, printer A and printer B would finish the [#permalink]
04 Mar 2013, 00:40
gauravnagpal wrote: Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A ? A. 600 B. 800 C. 1000 D. 1200 E. 1500 I know this question is relatively symol if make an equation in one vaibale ...
I tried to do it by applying the fundamental of A = Jobs per min * time ( the way we typically solve the work problems ) and i was stuck
I did jobs per minute A , 1/60
combined rate = 1/24
so rate of b = 1/24 - 1/60 = 1/40
but could not arrive at the solution ... i tried to form the equation by assuming x as the total numbe of pages So x/60+ x+5/40 = cld nt take ot forward from here
kindly see where am I losing the track ! total time taken by B = 24 * 60 / (60 -24) = 40 min. A take 60 min. B takes 40 min to complete a task. Now, divide the values given in option (in Ans) to get the rate per min. option A: 600 / 10 = 60 & 600/40 = 15...> this satisfies the condition given in question stem that printer B prints 5 pages a minute more than printer A ?
. therefore A
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Re: Working together, printer A and printer B would finish the
[#permalink]
04 Mar 2013, 00:40
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