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World problem - another one!! [#permalink]
26 Aug 2011, 01:19
00:00
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Difficulty:
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Question Stats:
0% (00:00) correct
0% (00:00) wrong based on 2 sessions
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
Re: World problem - another one!! [#permalink]
26 Aug 2011, 01:30
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
x-number to total copies sold
income from A = Qty of A* 1,
r/100* x (1+1.25) = p/100*x*1
income from A in terms of r = Income from A in terms of p
Re: World problem - another one!! [#permalink]
26 Aug 2011, 04:59
DeeptiM wrote:
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.
A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p
We know, A's revenue is r% of the total revenue
\(\frac{p}{125-0.25p}=\frac{r}{100}\)
OR
\(r=\frac{100p}{125-0.25p}\)
Likewise, please solve to get p in terms of r. This looks time consuming to me. _________________
Re: World problem - another one!! [#permalink]
26 Aug 2011, 08:31
fluke wrote:
DeeptiM wrote:
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.
A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p
We know, A's revenue is r% of the total revenue
\(\frac{p}{125-0.25p}=\frac{r}{100}\)
OR
\(r=\frac{100p}{125-0.25p}\)
Likewise, please solve to get p in terms of r. This looks time consuming to me.
Hi Fluke, Thanks a lot for the help.
I have posted the question in exactly similar terms in which it was presented to me..with no options however, the answer you derived is exactly what i have..
Re: World problem - another one!! [#permalink]
26 Aug 2011, 12:08
DeeptiM wrote:
Hi Fluke, Thanks a lot for the help.
I have posted the question in exactly similar terms in which it was presented to me..with no options however, the answer you derived is exactly what i have..
The question is from one of my practice set.
Really!!! My bad then. This really sounded strange!! Good that the answer matched luckily and it helped. thanks for posting. _________________
Re: World problem - another one!! [#permalink]
28 Oct 2011, 14:54
I didn't get it. P is the percent copies .... To find the A' and B' income, why u multiple "p"? shouldn't we multiple the real numbers, not percent, of copies sold?
Re: World problem - another one!! [#permalink]
29 Oct 2011, 01:12
fluke wrote:
DeeptiM wrote:
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.
A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p
We know, A's revenue is r% of the total revenue
\(\frac{p}{125-0.25p}=\frac{r}{100}\)
OR
\(r=\frac{100p}{125-0.25p}\)
Likewise, please solve to get p in terms of r. This looks time consuming to me.
Hi Fluke Could you please explain it in detail.. Please elaborate your answer..
Re: World problem - another one!! [#permalink]
29 Oct 2011, 05:27
1
This post received KUDOS
ashimasood wrote:
fluke wrote:
DeeptiM wrote:
A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?
DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.
A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p
We know, A's revenue is r% of the total revenue
\(\frac{p}{125-0.25p}=\frac{r}{100}\)
OR
\(r=\frac{100p}{125-0.25p}\)
Likewise, please solve to get p in terms of r. This looks time consuming to me.
Hi Fluke Could you please explain it in detail.. Please elaborate your answer..
Which part you didn't understand?
p percent of total copies sold were "A". If p=20%, then B must have sold 80% i.e. (100-p)%
If A sold p percent; B must have sold (100-p)%.
Now, let's suppose the number of copies sold be 100.
A sold = p B sold = 100-p
Money collected from A's sale=p*($1)=p Money collected from B's sale=(100-p)*($1.25)=125-1.25p Total income=p+125-1.25p=125-0.25p
Now, In a certain day, if r percent of the total income is from A;
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