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World problem - another one!! [#permalink]
26 Aug 2011, 01:19

00:00

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Difficulty:

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Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 2 sessions

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

Re: World problem - another one!! [#permalink]
26 Aug 2011, 01:30

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

x-number to total copies sold

income from A = Qty of A* 1,

r/100* x (1+1.25) = p/100*x*1

income from A in terms of r = Income from A in terms of p

Re: World problem - another one!! [#permalink]
26 Aug 2011, 04:59

DeeptiM wrote:

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.

A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p

We know, A's revenue is r% of the total revenue

\(\frac{p}{125-0.25p}=\frac{r}{100}\)

OR

\(r=\frac{100p}{125-0.25p}\)

Likewise, please solve to get p in terms of r. This looks time consuming to me. _________________

Re: World problem - another one!! [#permalink]
26 Aug 2011, 08:31

fluke wrote:

DeeptiM wrote:

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.

A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p

We know, A's revenue is r% of the total revenue

\(\frac{p}{125-0.25p}=\frac{r}{100}\)

OR

\(r=\frac{100p}{125-0.25p}\)

Likewise, please solve to get p in terms of r. This looks time consuming to me.

Hi Fluke, Thanks a lot for the help.

I have posted the question in exactly similar terms in which it was presented to me..with no options however, the answer you derived is exactly what i have..

Re: World problem - another one!! [#permalink]
26 Aug 2011, 12:08

DeeptiM wrote:

Hi Fluke, Thanks a lot for the help.

I have posted the question in exactly similar terms in which it was presented to me..with no options however, the answer you derived is exactly what i have..

The question is from one of my practice set.

Really!!! My bad then. This really sounded strange!! Good that the answer matched luckily and it helped. thanks for posting. _________________

Re: World problem - another one!! [#permalink]
28 Oct 2011, 14:54

I didn't get it. P is the percent copies .... To find the A' and B' income, why u multiple "p"? shouldn't we multiple the real numbers, not percent, of copies sold?

Re: World problem - another one!! [#permalink]
29 Oct 2011, 01:12

fluke wrote:

DeeptiM wrote:

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.

A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p

We know, A's revenue is r% of the total revenue

\(\frac{p}{125-0.25p}=\frac{r}{100}\)

OR

\(r=\frac{100p}{125-0.25p}\)

Likewise, please solve to get p in terms of r. This looks time consuming to me.

Hi Fluke Could you please explain it in detail.. Please elaborate your answer..

Re: World problem - another one!! [#permalink]
29 Oct 2011, 05:27

1

This post received KUDOS

ashimasood wrote:

fluke wrote:

DeeptiM wrote:

A store selld newspaper A at price of $1 and B at price of $1.25. In a certain day, if r percent of the total income is from A, and p percent of the total copies sold are A, in terms of r, p=?

DeeptiM: Please take care while posting question. This question looks as if you have formatted it in your own words; the options are also missing. Please mention the source of the question.

A's revenue: p*1=p B's revenue: (100-p)*1.25=125-1.25p Total revenue=p+125-1.25p=125-0.25p

We know, A's revenue is r% of the total revenue

\(\frac{p}{125-0.25p}=\frac{r}{100}\)

OR

\(r=\frac{100p}{125-0.25p}\)

Likewise, please solve to get p in terms of r. This looks time consuming to me.

Hi Fluke Could you please explain it in detail.. Please elaborate your answer..

Which part you didn't understand?

p percent of total copies sold were "A". If p=20%, then B must have sold 80% i.e. (100-p)%

If A sold p percent; B must have sold (100-p)%.

Now, let's suppose the number of copies sold be 100.

A sold = p B sold = 100-p

Money collected from A's sale=p*($1)=p Money collected from B's sale=(100-p)*($1.25)=125-1.25p Total income=p+125-1.25p=125-0.25p

Now, In a certain day, if r percent of the total income is from A;

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