bewakoof wrote:

3.|x|<1?

i |x+1|=2|x-1|

ii |x-3| is not equal to zero

lets take statement i. there are four possibles.

a. both modulas are +ve; x = 3.

b. both modulas are -ve; x = 3.

c. |x+1| is +ve and (2|x-1|) is -ve; x = 1/3.

d. |x+1| is -ve and (2|x-1|) is +ve; x = 1/3

so x is either 1/3 or 3. so statement i is not suff.

statement ii says |x-3| = 0. this alone is also not enough cuz we do not know the value of x and only know x is not equal to 3.

from i and ii, both, we know that x = 1/3 which is less tha 1.

So C is answer.