Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 21 Oct 2016, 05:22

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# x +1/x - 1)^2 If x in the equation above does not equal one

Author Message
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 67 [0], given: 0

x +1/x - 1)^2 If x in the equation above does not equal one [#permalink]

### Show Tags

02 Mar 2007, 03:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

(x +1/x - 1)^2

If x in the equation above does not equal one or zero and is replaced with - 1/x, the result is which of the following?

(x +1/x - 1)^2
(x - 1/x + 1)^2
(x^2 + 1/1 - x^2)
(x^2 - 1/1 + x^2)
- (x - 1/x + 1)^2

I hope everything is clear. If not just let me know.

Last edited by bz9 on 02 Mar 2007, 23:14, edited 1 time in total.
VP
Joined: 29 Apr 2003
Posts: 1403
Followers: 2

Kudos [?]: 27 [0], given: 0

### Show Tags

02 Mar 2007, 03:23
A.

Are you sure it is replaced with 1/X and not -1/X?
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 67 [0], given: 0

### Show Tags

02 Mar 2007, 23:15
Sorry, edited for clarity.

Can you guys work the problem?
Senior Manager
Joined: 18 Feb 2007
Posts: 253
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

02 Mar 2007, 23:46
bz9 wrote:
Sorry, edited for clarity.

Can you guys work the problem?

is everything typed properly now??
Senior Manager
Joined: 29 Jan 2007
Posts: 450
Location: Earth
Followers: 2

Kudos [?]: 61 [0], given: 0

### Show Tags

03 Mar 2007, 10:19
if new values is (-1/x)

then I got B)

[(x-1)/(x+1)]^2
Manager
Joined: 09 Jan 2007
Posts: 240
Followers: 2

Kudos [?]: 27 [0], given: 0

### Show Tags

03 Mar 2007, 19:26
after replacement...
[{(-1/x)+1} / {(-1/x)-1}]^2
=> [{(-1+x)/x}/{(-1-x)/x}]^2
=> [(x-1)/(-x-1)]^2
=> {(-1)(x-1)/(x+1)}^2
=> {(x-1)/(x+1)}^2

Senior Manager
Joined: 18 Feb 2007
Posts: 253
Followers: 1

Kudos [?]: 1 [0], given: 0

### Show Tags

03 Mar 2007, 20:33
bz9: you have typed "(x +1/x - 1)^2 "
did you really mean to type: "((x + 1)/(x-1))^2" ?

the two are definitely not the same
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 67 [0], given: 0

### Show Tags

03 Mar 2007, 22:08
Sorry,
I left this problem at work. I'll paste the entire question tomorrow.

My apologies
VP
Joined: 29 Apr 2003
Posts: 1403
Followers: 2

Kudos [?]: 27 [0], given: 0

### Show Tags

04 Mar 2007, 01:15
Agreed B with the new data
Display posts from previous: Sort by