Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 29 Mar 2015, 01:24

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# x>1, y>1, is x>y?

Author Message
TAGS:
Founder
Affiliations: AS - Gold, UA - Silver, HH-Diamond
Joined: 04 Dec 2002
Posts: 12717
Location: United States (WA)
GMAT 1: 750 Q49 V42
GPA: 3.5
WE: Information Technology (Hospitality and Tourism)
Followers: 2559

Kudos [?]: 11941 [0], given: 3825

x>1, y>1, is x>y? [#permalink]  19 May 2003, 15:41
Expert's post
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Can anybody solve this one?

x>1, y>1, is x>y?
i) squ x > y
ii) squ y < x

bb
Founder
Affiliations: AS - Gold, UA - Silver, HH-Diamond
Joined: 04 Dec 2002
Posts: 12717
Location: United States (WA)
GMAT 1: 750 Q49 V42
GPA: 3.5
WE: Information Technology (Hospitality and Tourism)
Followers: 2559

Kudos [?]: 11941 [0], given: 3825

Expert's post
brstorewala wrote:
I would say A

i am using this problem for the Question bank and it is an old one. I can't understand commander's last comment here
http://www.gmatclub.com/phpbb/viewtopic.php?t=368&highlight=another+hard

Any thoughts?
Manager
Joined: 28 Feb 2003
Posts: 100
Followers: 1

Kudos [?]: 3 [0], given: 0

from statement 1....

square root of any number x (where x>1), is less than the number itself.......
so if the square root of x is greater than y, then obviously x >y always.....so statement 1 is sufficient....

from statement 2.......

Assume y = 9 and x = 4........in this case
sqrt 9 < 4 ( i.e sqrt y < x) and y > x

Assume y = 9 and x = 12.....in this case
sqrt 9 < 12 ( i.e sqrt y < x) and x > y

so statement 2 is insufficient

Founder
Affiliations: AS - Gold, UA - Silver, HH-Diamond
Joined: 04 Dec 2002
Posts: 12717
Location: United States (WA)
GMAT 1: 750 Q49 V42
GPA: 3.5
WE: Information Technology (Hospitality and Tourism)
Followers: 2559

Kudos [?]: 11941 [0], given: 3825

Expert's post
brstorewala wrote:
from statement 1....

square root of any number x (where x>1), is less than the number itself.......
so if the square root of x is greater than y, then obviously x >y always.....so statement 1 is sufficient....

from statement 2.......

Assume y = 9 and x = 4........in this case
sqrt 9 < 4 ( i.e sqrt y < x) and y > x

Assume y = 9 and x = 12.....in this case
sqrt 9 < 12 ( i.e sqrt y < x) and x > y

so statement 2 is insufficient

Sorry for taking up your time. I was doing this one late at night and just did not understand the question. It is a one line explanation; sorry about that

bb
Intern
Joined: 10 Nov 2004
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 0

statement -2 is confusiing
surareroot y<x
please expl. why this is not sufficient
VP
Joined: 18 Nov 2004
Posts: 1442
Followers: 2

Kudos [?]: 20 [0], given: 0

"A" it is . From statment 1 we have x> y^2.....and for all x and y > 1 , x has to be > y...Suff

From statement 2 we have y < x^2...for x = 2 and y = 3, it is true, so x<y in this case , but for x = 4 and y = 3, above exp is still true but x > y...thus insuff.
Display posts from previous: Sort by