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x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y <

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x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y < [#permalink] New post 17 Mar 2004, 14:44
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x>1, y>1, is x>y?
i) sqrt x > y
ii) sqrt y < x
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 [#permalink] New post 17 Mar 2004, 14:52
A is sufficient.

B is not because

if sqrt(y) = 1.1 and x = 1.2 then Y = 1.21 > x
if sqrt(y) = 1.1 and x = 3 then Y = 1.21 < x
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 [#permalink] New post 17 Mar 2004, 14:53
(1) is enough
(2) is not

A

All statement two says is y<x^2, y could be < or > then x
  [#permalink] 17 Mar 2004, 14:53
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x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y <

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