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# x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y <

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Senior Manager
Joined: 11 Nov 2003
Posts: 355
Location: Illinois
Followers: 1

Kudos [?]: 0 [0], given: 0

x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y < [#permalink]  17 Mar 2004, 13:44
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
x>1, y>1, is x>y?
i) sqrt x > y
ii) sqrt y < x
SVP
Joined: 30 Oct 2003
Posts: 1797
Location: NewJersey USA
Followers: 5

Kudos [?]: 41 [0], given: 0

A is sufficient.

B is not because

if sqrt(y) = 1.1 and x = 1.2 then Y = 1.21 > x
if sqrt(y) = 1.1 and x = 3 then Y = 1.21 < x
Manager
Joined: 15 Mar 2004
Posts: 155
Location: New York
Followers: 1

Kudos [?]: 2 [0], given: 0

(1) is enough
(2) is not

A

All statement two says is y<x^2, y could be < or > then x
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