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# x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y <

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Senior Manager
Joined: 11 Nov 2003
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x>1, y>1, is x>y? i) sqrt x > y ii) sqrt y < [#permalink]

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17 Mar 2004, 14:44
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x>1, y>1, is x>y?
i) sqrt x > y
ii) sqrt y < x
SVP
Joined: 30 Oct 2003
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Location: NewJersey USA
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17 Mar 2004, 14:52
A is sufficient.

B is not because

if sqrt(y) = 1.1 and x = 1.2 then Y = 1.21 > x
if sqrt(y) = 1.1 and x = 3 then Y = 1.21 < x
Manager
Joined: 15 Mar 2004
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Kudos [?]: 2 [0], given: 0

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17 Mar 2004, 14:53
(1) is enough
(2) is not

A

All statement two says is y<x^2, y could be < or > then x
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